Food Energy Math
For this assignment you will have to calculate the food energy required to power various devices. You will be required to select 5 foods you have at your home and calculate how many of each item will be required to perform each mechanical or electrical process. Remember to calculate the per item calories; a serving of 2 chocolate sandwich cookies is 80 calories, one sandwich cookie is 40 calories.
For example, a coffee maker will require about 400 Watts of energy to run for an hour. 1 Kilocalorie is equal to 1.163 Watts, so the coffeemaker will require 343.9 Kilocalories to run for this length of time. If it could be converted to electricity how many fastfood cheeseburgers, (417 calories) would that require? Only 1 cheeseburger
Conversions:
1 Kcal- 1.163 Watts per hour
31,500 Kcal – 1 Gallon of gasoline

Answers

Answer 1

Answer:

https://courses.lumenlearning.com/cheminter/chapter/energy-in-food-and-nutrition/

Explanation:


Related Questions

Molecules on the surface of the ice escaping into the water happen in ————.

A. Boiling
B. Freezing
C. Condensation
D. Melting
E. Sublimation

Answers

D melting hope this was right

How many grams are in 2.4 moles of sulfur?

Answers

Answer:

76.96

Explanation:

A mole is Avagadro’s number of atoms of a substance. My periodic table of the elements gives the Gram Atomic Mass of natural sulphur is 32.066 grams/mole. Therefore, 2.4 moles would have a mass of 76.96 grams.

What is meant by X-ray​

Answers

Answer:

An X-ray, or X-radiation, is a penetrating form of high-energy electromagnetic radiation. Most X-rays have a wavelength ranging from 10 picometers to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz and energies in the range 124 eV to 124 keV.

Explanation:

An X-ray, or X-radiation, is a penetrating form of high-energy electromagnetic radiation. Most X-rays have a wavelength ranging from 10 picometers to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz (30×1015 Hz to 30×1018 Hz) and energies in the range 124 eV to 124 keV. X-ray wavelengths are shorter than those of UV rays and typically longer than those of gamma rays. In many languages, X-radiation is referred to as Röntgen radiation, after the German scientist Wilhelm Conrad Röntgen, who discovered it on November 8, 1895. He named it X-radiation to signify an unknown type of radiation. Spellings of X-ray(s) in English include the variants x-ray(s), xray(s), and X ray(s).

How do separate the pure ethanol from the mixture of coloured aqueous solution with ethanol​

Answers

Answer:

Fractional distillation is a method for separating a liquid from a mixture of two or more liquids. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. This method works because the liquids in the mixture have different boiling points. When the mixture is heated, one liquid evaporates before the other.

Given this slope equation, calculate the x-intercept (the point at which y = 0).

y = 0.523x + 16.8

Answers

Answer:

The answer is (-31.58, 0) when rounded to 2 decimal places.

How is heat involved in chemical reactions and processes

Answers

Most chemical reactions involve the breaking and formation of chemical bonds. It takes energy to break a chemical bond but energy is released when chemical bonds are formed. If more energy is released than consumed, then the chemical reaction evolves heat and is said to be exothermic.

(Have a good day!)

Answer:

Most chemical reactions involve the breaking and formation of chemical bonds. It takes energy to break a chemical bond but energy is released when chemical bonds are formed. If more energy is released than consumed, then the chemical reaction evolves heat and it called exothermic.

What force is required to accelerate a car at a rate of 4 m/s2 if the car has a mass of 37.5 kg?

Answers

Answer:150

Explanation:I think because f=MxA and the mass is 37.5 kg while acceleation is 4 m/s^2  and when you multiply that is gets 150 so F=150 N

How many moles of hydrogen atoms are there in 43g of pentathol C5H11OH

Answers

Answer:

Using your answer from Part A, calculate the volume of a mole of Na atoms (in cm3/mol ). Assume that the entire volume is occupied by Na atoms leaving no gaps or holes between adjacent atoms. (Answer A is V= 2.70*10^7)

Give the systematic (IUPAC) name for each molecule. This molecule has the condensed formula C H 3 C O C H 3. The oxygen atom has a double bond to the center carbon. systematic (IUPAC) name: This molecule has the condensed formula C H 3 C H 2 C H 2 C O C H 3. The oxygen atom has a double bond to carbon. systematic (IUPAC) name:

Answers

Answer: The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.

Explanation:

The basic rules for naming of organic compounds are :

1. First select the longest possible carbon chain. The longest possible carbon chain should include the carbons of double or triple bonds or functional group.For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

2. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and ketones by adding the suffix -one.;

3. The numbering is done in such a way that the carbon containing the functional group gets the lowest number. While writing the name, the word root is given first , followed by the position of carbon containing the functional group followed by the suffix.

The IUPAC name of [tex]CH_3COCH_3[/tex] propan-2-one and [tex]CH_3CH_2CH_2COCH_3[/tex] is pentan-2-one.

A gas has an initial pressure of 633 torr and an initial volume of 87.3 mL. What is its new pressure if volume is changed to 45.0 mL?

Answers

Answer:

1230 torr

Explanation:

To solve this problem, all you need to do is apply Boyle's Gas Law: P1V1 = P2V2.

633 torr x 87.3 mL = 45.0 mL x P2 (Unknown)

P2 = 1230 torr

(Remember, we need to follow sig fig rules.)

The statement of the new pressure is "1228.02"

What is a pressure?

The physical force exerted on an item is known as pressure. The pressure and volume of the gas are maintained at a constant temperature according to Boyle's law, that is pressure and volume are inversely proportional.

P1.V1 = P2.V2

Now,

P1 = 633 torr and V1 = 87.3 mL

V2 = 45.0 mL

In order to find the new volume, substituting these values into Boyle’s law, we get

[tex]P2\;=\;\frac{P1.V1}{V2} \\P2\;=\;\frac{(633\; torr).(87.3\;mL)}{(45.0\;mL)} \\[/tex]

P2 = 1228.02 torr

Hence the correct answer is 1228.02 torr.

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When an acid is added to a base, which if the following changes in pH might be observed?
A. An increase from 7 to 8
B. An increase from 3 to 8
C, A decrease from 7 to 6
D. A decrease from 9 to 5

Answers

Im just guessing, so i think is A

Calculate the pH of a solution prepared by dissolving 1.60 g of sodium acetate, CH3COONa, in 50.0 mL of a 0.10 M acetic acid, CH3COOH (aq). Assume the volume change upon dissolving the sodium acetate is negligible. Ka of CH3COOH is 1.75 × 10^-5.​

Answers

Answer:

pH = 5.35

Explanation:

Given 1.60 grams sodium acetate (NaOAc(aq))*** added to 50ml of 0.10M acetic acid (HOAc(aq)) solution.

Applying common ion effect keeping in mind that the addition of NaOAc provides the common-ion (OAc⁻).

     HOAc(aq) ⇄          H⁺(aq)            +                 OAc⁻(aq)

I      0.10m          1.32 x 10⁻³M ≈ ∅M*     (1.6g/82.03g/mol) / 0.050L = 0.39M

C       -x                         +x                                0.39M + x ≈ 0.39M**

E    0.10M - x                  x                                    0.39M

      ≈ 0.10M

Ka = [H⁺][OAC⁻]/[HOAC] => [H⁺] = Ka·[HOAc] / [OAc⁻]

[H⁺] = (1.75 X 10⁻⁵)(0.10) / (0.39) = 4.5 x 10⁻⁶M

∴ pH = -log[H⁺] = -log(4.5 x 10⁻⁶) = -(-5.35) = 5.35

_______________________________________________

* [H⁺] before adding NaOAc = SqrRt(Ka · [HOAc]) = SqrRt(1.75 x 10⁻⁵· 0.10) = 1.32 x 10⁻³M. Since this concentration value is so small, the initial [H⁺] is assumed to be zero molar (∅M).

** The added [H⁺] is negligible and dropped in the ICE table. That is, adding ~[H⁺] in the order of 10⁻³M does not change the H⁺ ion concentration sufficiently to affect problem outcome and is therefore dropped in the ICE table.

*** Acetic Acid and Sodium Acetate are frequently written HOAc and NaOAc where the OAc⁻ anion is the acetate ion (CH₃COO⁻) for brevity.

We have that the  pH of the solution  derived to be

[tex]pH=5.0969[/tex]

From the Question we are told that

Mass of CH3COONa=1.60g

Volume of CH3COONa v=40ml

0.10 M acetic acid

Ka of CH3COOH is 1.75 × 10^-5.​

Generally the equation for the  pH  is mathematically given as

[tex]pH = pKa + log\frac{ base}{acid}[/tex]

Where

[tex]pka = -logKa\\\\pKa = -log(1.75*10^{-5})[/tex]

Generally

[tex]Moles\ of\ CH3COONa = \frac{Mass of CH3COONa}{Molar mass of CH3COONa}[/tex]

[tex]Moles of CH3COONa=\frac{1.15}{82.03}[/tex]

[tex]Moles of CH3COONa=0.0140moles[/tex]

And

[tex]base=\frac{ 0.0140moles}{(64.0/1000)}\\\\base=0.21875moles[/tex]

Therefore returning to the initial pH equation

[tex]pH = pKa + log\frac{ base}{acid}\\\\pH = -log(1.75*10^{-5}) + log\frac{ 0.21875}{0.10}[/tex]

[tex]pH=5.0969[/tex]

In conclusion

The  pH of the solution  derived to be

[tex]pH=5.0969[/tex]

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Arrange the following molecules in order of increasing bond polarity (highest bond polarity at the bottom):

a. NF3
b. NCl3
c. Nbr3
d. CF4

Answers

NF3– 0.94– third
NCl3–0.12– second
NBr3–0.08– first
CF4–1.43– fourth

NBr3—NCl3—NF3—CF4
Lowest. Highest

If you were to describe America, what would you describe? In one word​

Answers

Answer:

Happy..

grateful

freedom

Explanation:

Answer:

huge

Explanation:

wally fluoride is an imaginary gaseous
compound with a molar mass of 314.2 g/mol.
(a) What is the density of wollmanium fluoride at 425 K
and 165 torr?

Answers

Answer:

[tex]\rho =1.96\frac{g}{L}[/tex]

Explanation:

Hello there!

In this case, since this imaginary gas can be modelled as an ideal gas, we can write:

[tex]PV=nRT[/tex]

Which can be written in terms of density and molar mass as shown below:

[tex]\frac{P}{RT} =\frac{n}{V} \\\\\frac{P}{RT} =\frac{m}{MM*V}\\\\\frac{P*MM}{RT} =\frac{m}{V}=\rho[/tex]

Thus, by computing the pressure in atmospheres, the resulting density would be:

[tex]\rho = \frac{165/760 atm * 314.2 g/mol}{0.08206\frac{atm*L}{mol*K}*425K} \\\\\rho =1.96\frac{g}{L}[/tex]

Best regards!

List the three different temperature scales

Answers

Answer:

Celcius

Farenheit

Kelvin

Explanation:

2.56 x 10^13 molecules of HgO equates to how many moles of HgO?

Answers

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\[/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

We have

[tex]n = \frac{2.56 \times {10}^{13} }{6.02 \times {10}^{23} } \\ \\ \\ = 4.25 \times {10}^{ - 11} \: \: \: moles[/tex]

Hope this helps you

if eleanor starts with 25.00 ml of a weak acid (the concentration is 0.1084 m), then how many ml of 0.1817 m naoh has to be added to reach the equivalence point

Answers

Answer:

14.91 mL

Explanation:

Assuming the weak acid is monoprotic, we can solve this problem using the equation:

C₁V₁=C₂V₂

Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.

We input the data:

25.00 mL * 0.1084 M = 0.1817 M * V₂

And solve for V₂:

V₂ = 14.91 mL

The volume of 0.1817 M NaOH has to be added to reach the equivalence point is 14.91 mL.

How we calculate the volume?

Volume for the given solution will be calculated from the below equation:

M₁V₁ = M₂V₂, where

M₁ = Molarity of weak acid = 0.1084 M

V₁ = volume of weak acid = 25 mL

M₂ = molarity of NaOH = 0.1817 M

V₂ = volume of NaOH = to find?

On putting all these values on the above equation and calculate for V₂ as:
V₂ = (0.1084)(25) / (0.1817) = 14.91 mL

Hence required volume is 14.91 mL.

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All of the following are strong acids except

A. Nitric acid
B. Hydrochloric acid
C. Sulfuric acid
D. Acetic acid

Answers

Answer:

acetic acid

Explanation:

Acetic acid because it presents in solution primarily as whole.

A light year is a measurement of ___________.

Which word best completes the sentence?

Answers

Answer:

distance

Explanation:

(=^w^=) it is literally just the distance a beam of light moves in one year

Answer:

It is distance( they were right)

Explanation:

Took test

An inventor claims to have developed a new perfume that lasts a long time because it doesn't evaporate. Comment on this claim.
a. This would be impossible to make because the perfume would have to be pressurized in order to not evaporate.
b. This product is sure sweep the market making many happy customers.
c. In order to smell something, the molecules must evaporate and reach your nose. If the new perfume doesn't evaporate, it will not have an odor.
d. A perfume that does not evaporate could be toxic since the molecules never leave the skin.

Answers

Answer:

C

Explanation:

Perfume needs to evaporate in order to smell.  If this perfume didn't evaporate, it would stay as a liquid and never smell.  

It wouldn't be D, as no toxic perfumes is sold.

It's not A because perfume doesn't have to be pressurized in order to not evaporate.

It's not B, as it is a hasty conclusion to the claim.  Plus, if the perfume did have an odor, even while not evaporating, the sales would be low as the product is that good.  

b) How many kilojoules of heat will be released by the combustion of 22.52 g of this liquid at
constant pressure?
C2H5OH burning in a simple alcohol lamp is -1277.3kJ/mol​

Answers

Answer:

Explanation:

You realize that C2H5OH releases -1277.3kJ/mol. We need to convert this to the amount based on the question. We that 22.52g of C2H5OH = 0.48884 mol.

This means that it will release (-1277.3)(0.48884) = 624.40 KJ of heat will be released. Note the negative sign is not necessary here (I think) because it says how much is released and not the change in heat of the system so it should be positive.

A small file or organization use a payroll program for calculating staff wages each month each employee has a unique payroll number had is paid a fixed hourly rate which may be different for different employee. the system uses a master file containing long term details such as name Address, hourly,rate of pay and total pay for a year .the key field in the master file is the payroll number and the filled is stored in this field .each month by each a transaction file is produced containing details of the hours worked during that month by each employee,(a)state the type of processing used in this application and explain why this type of processing is suctable,(b) describe the processing take place each month when the payroll program is run staff with unsorted transaction file and end after the master file has been updated the pay slips have been printed,(c) explain what would happen during the processing of an employee payroll number had been entered incorrectly into the transaction file​

Answers

Answer:

the company is now aarav and its CEO of samruddhi and is the CEO in meeting with holika and will come in to help with holika as brainlyiest as the company's chief financial adviser to solve di problems

Explanation:

it was the most common thing that happened in my first pregnancy in my first year and I m and the other girl Bo.. were pretty good vibes for the last day of samruddhi but they are still very much a many years after I was knowing that

H3O+ is called the

A. Hydroxide ion.
B. Hydrogen ion.
C. Hydrate ion.
D. Hydronium ion

Answers

A.hydroxide ion

Explanation:

because it consists 3 hydrogen and 1 oxygen with + ion

Given the balanced equation:
2H2 + 02 --> 2H20

How many grams of H20 is produced if you have 7g of O2

Answers

Answer: 7.88375g

Explanation:

Here is the dimensional analysis table

7g O2 | 1 mol O2 | 2 mol H2O | 18.02 g H2O

| 32 g O2 | 1 mol O2 | 1 mol H2O

You use grams to convert to moles of O2, then use that to find grams of H20

Determine the concentration of a solution of sodium hydroxide (NaOH) using a 0.500M Potassium Hydrogen Phthalate (KHP) standard solution. Acid-base indicator phenolphthalein is added in its (colorless) acidic form to a precise volume sample of KHP. The base NaOH is slowly added to the same of KHP. Once all the KHP has reacted with the base, the first excess drop of NaOH will cause the indicator to convert to its basic (pink) form.

Answers

Answer:

0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL

Explanation:

The KHP reacts with NaOH as follows:

KHP + NaOH → KNaP + H₂O

Where 1 mole of KHP reacts per mole of KNaP

That means, the moles of KHP added to the NaOH solution = Moles NaOH at equivalence point. With the moles of NaOH and the volume in liters we can find the molar concentration of NaOH.

Assuming the volume added of KHP was 25.50mL and the solution of NaOH contains 30.0mL (0.0300L), the concentration of the NaOH is:

Moles KHP = Moles NaOH:

25.50mL = 0.02550L * (0.500mol / L) = 0.01275 moles KHP = Moles NaOH

Molarity NaOH:

0.01275 moles NaOH / 0.0300L =

0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL

Ammonia is produced by the chemical reaction of hydrogen and nitrogen

N2 + 2H2 → 2NH3

How many moles of H2 are needed to react with 1.8 moles of N2

Answers

Answer:

3.6 mol H₂

Explanation:

N₂ + 2H₂ → 2NH₃

In order to convert from N₂ moles to H₂ moles we need to use a conversion factor. This conversion factor has to have N₂ moles in the denominator and H₂ moles in the numerator, using the stoichiometric coefficients of the reaction, as follows:

1.8 mol N₂ * [tex]\frac{2molH_2}{1molN_2}[/tex] = 3.6 mol H₂

Given the following set of data from the decomposition of hydrogen peroxide,
how is the initial rate of the reaction (between time 0 and 300 seconds)
different from the rate of the reaction between 1800 and 3000 seconds?
[H202 M
Time (s)
2.0
0
1.6
300
1.4
600
1.1
1200
0.72
1800
0.15
3000

Answers

Answer:

what it mean I don't know

Aeronautical engineers have to consider the weight, trust, life, and drag of an airplane to determine whether or not…

Answers

Answer:

the plane will crash, or if it is usable or not.

the maximum amount of copper sulfate that can be dissolved in 45.0g of water at 70C is 20.0g. what is the solubility of copper sulfate at that temperature?
(in grams per 100g water)​

Answers

Answer:

That depends on the amount. Solubility is the maximum amount of salt dissolved in 100 g of water. So, if the amount is within limit, then yes. Solubility of anhydrous copper sulfate is 24.3 g/100 g water, so it is not bad. Put it in perspective, the solubility of NaCl is about 35 g/100 g water at room temperature. If the amount of copper sulfate is unknown, qualitative I'd say solid copper sulfate will dissolve in water completely.

Explanation:

If you use the pentahydrate CuSO4.5H2O then the solubility at 20°C is 20.8g/100ml H2O

If you use the anhydride, CuSO4. then the solubility at 20°C is 36.2g/100ml H2O

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