Answer:
100 joules (J).
Explanation:
Converting Units - 36 km/h = 10 m/s
72 km/h = 20 m/s ( 1 km/h = 5/18 m/s)
Change in speed = 20 - 10 = 10 m/s
Applying the Work-Energy theorem,
[tex]Work done = \frac{1}{2} 2 (10)^2[/tex]
= 100 J.
Please help!!!!! This is for science and I don’t understand
Answer:
the correct one is B
Explanation:
In this exercise, indicate that crocodiles need a warm climate to survive.
The current climate in the western Colorado region where the temperature is 53ºF (11.7ºC) does not allow them to survive, therefore the appearance of fossil crocodiles and fossil subtropical plants and a clear indication that the climate in these regions was much more warm
when checking the answers the correct one is B
Can somebody help me with this i cannot learn it online, a walk through would be nice :)
Answer:
1. 5 V
2. A₂ = 1.2 A
Explanation:
1. Determination of the voltage measured at R₃.
Voltage at R₁ (V₁) = 1 V
Voltage at R₂ (V₂) = 6 V
Total voltage (Vₜ) = 12 V
Voltage at R₃ (V₃) =.?
Vₜ = V₁ + V₂ + V₃
12 = 1 + 6 + V₃
12 = 7 + V₃
Collect like terms
12 – 7 = V₃
V₃ = 5 V
Thus, the voltage measured at R₃ is 5 V
2. Determination of A₂.
From the circuit diagram, we can see that the resistors are in series arrangement. This means that the same current will pass through each resistor.
Thus,
A₂ = A₁ = 1.2 A
A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor is a stationary 375-Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 1.80 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 2.75 Hz. Ignoring any reflections of sound in the room and using 343 m/s for the speed of sound, determine the amplitude (in m) of the simple harmonic motion.
Answer:
[tex]0.361\ \text{m}[/tex]
Explanation:
[tex]f_s[/tex] = Frequency of source = 375 Hz
[tex]\Delta f[/tex] = Difference between the maximum and minimum sound frequencies = 2.75 Hz
v = Speed of sound in air = 343 m/s
T = Time period = 1.8 s
[tex]v_m[/tex] = Maximum speed of the microphone
We have the relation
[tex]\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}[/tex]
Amplitude is given by
[tex]A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}[/tex]
The amplitude of the simple harmonic motion is [tex]0.361\ \text{m}[/tex].
PLEASE HELP ME :( I've tried solving it many times but my teacher keeps saying its wrong i really need help
Answer:
The charge on each end of the wire produces what we call an electric field. The electric field makes negative electrons want to travel towards the positive end of the wire (the end with not enough electrons).
the answer is d because it's going to positive.
is am alright? let me know.
An object moves from point A to B to C to D and finally to A
along the circle shown in the figure below.
a) Find the distance covered by the moving object.
b) Find the magnitude of the displacement of the object.
Answer:
a) The distance covered by the moving object is approximately 18.85 km
b) The magnitude of the displacement of the object is 0 (no displacement)
Explanation:
From the drawing, we have;
The sale of the drawing is 1 unit = 1 km
The radius of the circle in the drawing along which the object moves = 3 units
Therefore;
The radius of the circle along which the object moves, r = 1 km/unit × 3 units = 3 km
a) The distance covered by the object that moves from point A to B to C to D and finally to A is equal to the circumference of the circle
Therefore;
The distance covered by the moving object, d = 2·π·r
By pugging the value for r = 3 km
d = 2 × π × 3 km = 6·π km ≈ 18.85 km
The distance covered by the moving object, d ≈ 18.85 km
b) The displacement = The object's change in position
The initial position of the object = Point A
The final position of the object = Point A
Therefore, the displacement of the object, A = No displacement = 0 (No difference between the initial and final location of the object
A plumber is going to put two pipes in a wall, one in front and one in back. The pipes will be touching once they are installed. Both pipes are the same size and have the same number of molecules. The diagram above shows the pipes now, before they have touched. Use the information in the diagram to answer the question.
How does the temperature of the front pipe compare with the temperature of the back pipe before the pipes touch? What will happen after the pipes have been touching for a while?
Answer:
They become the same exact tempature
Explanation:
Since they got connected it should be the same.
the temperature of the front pipe compare with the temperature of the back pipe before the pipes touch by using same temperature.
what is temperature ?Temperature is the measure of hotness or coldness expressed in terms of any of several arbitrary scales and it indicate the direction in which heat energy will spontaneously flow from a hotter body to a colder body.
It is not the equivalent of the energy of a thermodynamic system like burning match is at a much higher temperature than an iceberg whereas the total heat energy contained in an iceberg.
Temperature which is similar to pressure or density known as intensive property that is independent of the quantity of matter is considered as distinguished from extensive properties, such as mass or volume.
For more details regarding temperature, visit
https://brainly.com/question/23411503
#SPJ2
A force is used to lift mass to a height of 8 m does 1040 J of work. How much force is used?
Answer:
[tex]\boxed {\boxed {\sf 130 \ Newtons }}[/tex]
Explanation:
Work is the energy transferred to or from an object when force is applied to cause displacement. It is the product of force and displacement.
[tex]W=F*s[/tex]
The displacement (s) is 8 meters and the work (W) is 1,040 Joules. Substitute these values into the formula.
[tex]1040 \ J= F* 8 \ m[/tex]
First, let's convert the units. This will make the question easier later on. 1 Joule is equal to 1 Newton meter, so the 1040 J of work equal 1040 N*m.
[tex]1040 \ N*m= F * 8 \ m[/tex]
Since we are solving for the force (F), we must isolate the variable. It is being multiplied by 8 meters and the inverse of multiplication is division. Divide both sides by 8 m.
[tex]\frac {1040 \ N*m}{8 \ m}= \frac{F * 8 \ m}{8 \ m}[/tex]
[tex]\frac {1040 \ N*m}{8 \ m}=F[/tex]
The meters cancel out, hence our earlier unit conversion.
[tex]130 \ N = F[/tex]
A force of 130 Newtons is used.
Paper clips, nails, and scissors all act as which of the following?
electromagnets
ion magnets
temporary magnets
I think its ion magnets correct me if I'm wrong
What would happen to the two balls if one of them were kept positively charged and the charge on the other ball were slowly increased, making it more and more positive? View Available Hint(s) What would happen to the two balls if one of them were kept positively charged and the charge on the other ball were slowly increased, making it more and more positive? The balls would begin to move closer together. The balls would not move relative to each other. The balls would begin to move farther apart.
Answer:
the balls would move closer to each other
Explanation:
In regions of the cardiovascular system where there is steady laminar blood flow, the shear stress on cells lining the walls of the blood vessels is about 20 N / M2. If the shear strain is about 0.008, estimate the shear modulus for the affected cells.
Answer:
Shear Modulus = 2500 Pa = 2.5 KPa
Explanation:
The shear modulus is defined as the ratio between the shear stress and the shear strain. Hence, the shear modulus, in this case, can be calculated by the use of the following formula:
[tex]Shear\ Modulus = \frac{Shear\ Stress}{Shear\ Strain}\\[/tex]
we have,
shear stress = 20 N/m²
shear strain = 0.008
Therefore,
[tex]Shear\ Modulus = \frac{20\ N/m^2}{0.008}\\\\[/tex]
Shear Modulus = 2500 Pa = 2.5 KPa
Suppose you are working on green house, which light you would
use for their growth?
Answer:
Fluorescent lighting is usually used.
Explanation:
Answer:
HPS lighting or LED light
Explanation:
HPS light is well known choice with a proven track record for growers. While you can also use LED lights as an alternative to incandescent or HPS fixtures for day length extension.
An elephant's legs have a reasonably uniform cross section from top to bottom, and they are quite long, pivoting high on the animal's body. When an elephant moves at a walk, it uses very little energy to bring its legs forward, simply allowing them to swing like pendulums. For fluid walking motion, this time should be half the time for a complete stride; as soon as the right leg finishes swinging forward, the elephant plants the right foot and begins swinging the left leg forward.
Answer:
is this the full question?
Explanation:
A system releases 150 kJ of heat while 10 kJ of work is done on the system by
the surroundings. Calculate the change in internal energy (in kJ).
Answer:
160J OR 140J
Explanation:
Depends on teacher which formula your teacher uses.
U=Q+W OR U=Q-W
Method 1:
U=150+10J=160
U=150-10=140J
GIVING BRAINLIEST PLEASE HELP!!
-if you answer correctly ill give you brainliest which will give you 25pts-
Answer:
A, and D are the answers
Explanation:
The pulley. It is located where the bicycle chain and gears are. The chain is wrapped around the pulley which turns and causes the wheel to turn on its axle.
A laser pulse of duration 25 ms has a total energy of 1.4 J. The wavelength of this radiation is
567 nm. How many photons are emitted in one pulse? Let 1 eV = 1.60 x 10-19 J, the mass of
an electron m=9.11 10-31
kg, the speed of light c= 3.00 x 108 m/s, and Planck's constant h
= 4.136 10-15 eV .s.
Answer:
n = 4 x 10¹⁸ photons
Explanation:
First, we will calculate the energy of one photon in the radiation:
[tex]E = \frac{hc}{\lambda}\\\\[/tex]
where,
E = Energy of one photon = ?
h = Plank's Constant = 6.625 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m
Therefore,
[tex]E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{5.67\ x\ 10^{-7}\ m}[/tex]
E = 3.505 x 10⁻¹⁹ J
Now, the number of photons to make up the total energy can be calculated as follows:
[tex]Total\ Energy = nE\\1.4\ J = n(3.505\ x\ 10^{-19}\ J)\\n = \frac{1.4\ J}{3.505\ x\ 10^{-19}\ J}\\[/tex]
n = 4 x 10¹⁸ photons
A type of organism that makes its own food. __________
The highest taxonomic classification of organisms.__________
The process through which organisms make new organisms of the same kind. _______
The taxonomic classification below domains._________
A type of organism that is made of more than one cell and is more specialized and eukaryotic.__________
A characteristic passed from female and male parents to their offspring.________
FILL IN THE BLANKS PLEASEEE WILL GIVE BRAINLIEST AND 50 POINTS
Answer:
1. An autotroph
2. Domain
3. Reproduction
4. Kingdom
5. Multicellular Organism
6. Genetic trait
Explanation: Took Bio honors 1 & 2
Two charges are separated by a distance r. The distance between the charges is tripled to 3r. If the original force between the charges was 45N what is the new force between the charges A.5N B.15N C.75N D.135N
Answer:
5N
Explanation:
The formula formula for calculating the force between charges is expressed as;
F = kq1q2/r²
If two charges are separated by a distance r and a force between them is 45N, then;
45 = kq1q2/r² ....1
If the distance between the charges is tripled to 3r, then;
F = kq1q2/(3r)²
F = kq1q2/9r² ... 2
Divide both expressions
45/F = (kq1q2/r²)/(kq1q2/9r²)
45/F = kq1q2/r² * 9r²/kq1q2
45/F = 9
9F = 45
F = 45/9
F = 5N
Hence the new force between them will be 5N
In this system, ___________________ energy from the sunlight causes the solar panel to create ___________________ energy which flows into the incandescent light bulb. In the light bulb, the ___________________ energy is transformed into two different types of energy: ___________________ energy and ___________________ energy.
Answer:
solar, heat,heat, light
particles q1, q2, and q3 are in a straight line. particles q1 = -5.00 x 10^-6 C, q2 = -5.00 x 10^-6 C. .5 between each what is the net force on q3
Answer:
1.12
Explanation:
Acellus
Answer: +1.12
Explanation:
This answer works for Acellus! :)
Geothermal energy is an alternative energy source, although it is not resourceful enough to replace more than a minor amount of the Earth’s energy needs. Why is this?
Answer: However, it is not resourceful enough to replace more than a minor amount of the Earth's energy needs. Drilling through the Earth to reach areas hot enough to create steam is possible, but very expensive and difficult. .
Explanation:
Two cars of the same mass have different velocities. Which car has more momentum?
Answer:
The car with the higher velocity would have a more impactful momentum.Given equal time periods, which statement about radioactive waste is correct?
A. Radioactive decay and nuclear fission always generate the same amount of waste.
B. Nuclear fusion generates less radioactive waste than radioactive decay does.
C. Nuclear fusion generates less radioactive waste than nuclear fission does.
D. Nuclear fission generates less radioactive waste than radioactive decay does.
A person starts running from 2 m/s to 6 m/s in 2 seconds.
Calculate the person's acceleration.
Var
Variables:
Solve:
F
Formula:
Answer:
2 m/s²
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 2 m/s
Final velocity (v) = 6 m/s
Time (t) = 2 s
Acceleration (a) =?
The acceleration of the person can be obtained as follow:
v = u + at
6 = 2 + (a×2)
6 = 2 + 2a
Collect like terms
6 – 2 = 2a
4 = 2a
Divide both side by 2
a = 4 / 2
a = 2 m/s²
Therefore, the acceleration of the person is 2 m/s²
It takes 5000 J of work to lift a crate to a height of 5 m in 10 s of time.. Calculate the power.
Answer:
P = 500 W
Explanation:
Given that,
Work done to lift a crate to a height of 5 m is 5000 J
It takes 10 s
We need to find the power of the crate. We know that power is the rate of doing work. Mathematically, it can be given by :
[tex]P=\dfrac{W}{t}\\\\P=\dfrac{5000}{10}\\\\P=500\ W[/tex]
So, the power of the crate is equal to 500 W.
In a car collision, is it better for the passenger if the change in momentum is over a short period of time or a long period of time?
Explanation:
The force on the passenger will be F = ma
Here, m does not change, but a is the variable.
If the cars slows down very fast, the acceleration will be higher, and thus the force will be higher.
If the acceleration is lower, the force will be lower as well, which would be the most desirable scenario for the passenger.
a bullet of mass 120g is fired horizontally into a fixed wooden block with a speed of 20m\s. The bullet is brought to rest in a wooden block in 0.1secs by a constant resistance
calculate the;(I) magnitude of the resistance
(ii) distance moved by the bullet in the wood
Answer:
1) F = 24 N
2) Distance = 1 m
Explanation:
We are given;
Mass; m = 120 g = 0.12 kg
Initial velocity; u = 20 m/s
Final velocity; v = 0 m/s since it came to rest.
Time; t = 0.1 s
We can calculate acceleration from Newton's first equation of motion;
a = (v - u)/t
a = (0 - 20)/0.1
a = -200 m/s²
1) magnitude of the resistance will be;
F = ma
F = 0.12 × (-200)
F = -24 N
Since, we are dealing with the magnitude, we will take the absolute value. Thus, F = 24 N
2) To find the distance moved by the bullet, we know that;
Distance = Average speed × time
Thus;
Distance = ((v + u)/2) × t
Distance = ((0 + 20)/2) × 0.1
Distance = 1 m
Una caja con medicina es lanzada desde un avión localizado a una distancia vertical de 340 m por encima de un río. Si el avión lleva una velocidad horizontal de 70 m/s¿Qué distancia horizontal recorrerá la caja con medicina antes de caer al río?
Answer:
La distancia horizontal que recorrerá la caja con medicina antes de caer al río es 583.1 metros.
Explanation:
Una caja con medicina es lanzada desde un avión localizado a una distancia vertical de 340 m por encima de un río. Este movimiento posee una composición en dos dimensiones: uno horizontal sin aceleración, y el otro vertical con aceleración constante debido a la gravedad. Por lo que se trata de un movimiento rectilíneo uniforme (MRU) en su trayectoria horizontal o eje horizontal (es decir, su velocidad es constante) y un movimiento uniformemente variado (MRUV) en su trayectoria vertical o en el eje vertical (es decir, su aceleración es constante).
En este caso, son conocidos los datos, considerando el sistema de referencia de la imagen:
Vy = 0 m/s (trayectoria vertical) Vx = 70m/s (velocidad horizontal) hi = 340 m (altura inicial) g = -9,8 m/s² hf = 0 m (altura final. Cuando la caja de medicina cae al río, su altura será 0 m)En el caso del MRUV, la posición puede calcularse mediante la expresión:
Posición final= Posición inicial + Velocidad inicial*t + [tex]\frac{1}{2}[/tex]*a*t²
donde a es la aceleración y t el tiempo transcurrido.
En este caso, reemplazando los datos conocidos, teniendo en cuenta que el MRUV sucede en la trayectoria vertical y que la aceleración es el valor de la gravedad:
0 m= 340 m + 0 m/s*t + [tex]\frac{1}{2}[/tex]* (-9.8 m/s²)* t²
Resolviendo:
-340 m= [tex]\frac{1}{2}[/tex]* (-9.8 m/s²)* t²
[tex]\frac{-340 m}{\frac{1}{2} *(9.8\frac{m}{s^{2} } )} =t^{2}[/tex]
69.39 s²= t²
t= √69.39 s²
t= 8.33 s
La posición en MRU se obtiene mediante:
Posición final= Posición inicial + velocidad* tiempo
Con los datos conocidos y el tiempo calculado previamente, es posible calcular la distancia horizontal que recorrerá la caja con medicina antes de caer al río, siendo la posición inicial en x igual a cero:
Posición final= 0 m + 70m/s* 8.33 s
Posición final= 583.1 m
La distancia horizontal que recorrerá la caja con medicina antes de caer al río es 583.1 metros.
Veremos que la distancia horizontal que recorre la caja es 583.1 metros.
¿Como encontrar la distanca horizontal recorrida?Recordar que la velocidad vertical y horizontal son independientes.
Aqui, lo primero que debemos hacer es encontrar el tiempo que la caja tarda en llegar al suelo.
Para ello usamos la ecuación de movimiento vertical:
p(t) = (-4.9 m/s^2)*t^2 + v*t + h
Donde el primer termino representa la gravedad, el segundo la velocidad inicial (que es cero en este caso) y el tercero la altura inicial, que es 340m.
p(t) = (-4.9 m/s^2)*t^2 + 340m
La caja llegara al suelo cuando la función de arriba sea igual a cero:
(-4.9 m/s^2)*t^2 + 340m = 0
t = √(340m/(4.9 m/s^2)) = 8.33 s
Es decir, la caja tarda 8.33 segundos en llegar al suelo.
Esto significa que la caja se va a mover horizontalmente durante 8.33 segundos con una velocidad de 70m/s (la que tenía el avion). Es decir, la distancia horizontal que se mueve la caja es :
D = 8.33s*(70m/s) = 583.1 m
Sí quieres aprender más sobre ecuaciones de movimiento, puedes leer:
https://brainly.com/question/25316464
1.What is the kinetic energy of an object with a velocity of 7m / s and a mass of 14kg
2. What is the kinetic energy of an object with a velocity of 5m / s and a mass of 5kg
Helppppp!
Answer:
Explanation:
The formula for KE is
[tex]KE=\frac{1}{2}mv^2[/tex] and we fill in to solve for KE:
[tex]KE=\frac{1}{2}(14)(7.0)^2[/tex] I used 2 significant digits in the velocity because 1 isn't accurate enough. Therefore, my answer will be rounded to 2 sig fig's:
KE = 340 J (rounded from 343). And we do the exact same thing in #2:
[tex]KE=\frac{1}{2}(5.0)(5.0)^2[/tex] (Used 2sig fig's for both the mass and the velocity) to get
KE = 63 J (rounded from 62.5)
A vertical piston-cylinder device initially contains 0.1 m^3 of air at 400 K and 100 kPa. At this initial condition, the piston is resting on a stop. The piston-cylinder device is connected to a supply line with air at 400 K and a pressure of 500 kPa. The valve between the supply line and the piston-cylinder device is opened and is left open until the pressure in the piston-cylinder device reaches 500 kPa. The piston is observed to start moving when the pressure in the cylinder is 200 kPa and the piston continues to rise until it reaches a second stop. At the second stop, the piston-cylinder volume is 0.2 m^3 . The final temperature and pressure in the piston-cylinder device are 440 K and 500 kPa, respectively. Determine the heat transfer to or from the piston-cylinder device for the filling process Determine heat transfer (kJ) during the entire process.
Answer:
[tex]Q=-38.15kJ[/tex]
Explanation:
From the question we are told that
Piston-cylinder initial Volume of air [tex]v_1=0.1 m^3[/tex]
Piston-cylinder initial temperature [tex]T_1=400k[/tex]
Piston-cylinder initial pressure [tex]P_1= 100kpa[/tex]
Supply line temperature[tex]T_s=400k[/tex]
Supply line pressure [tex]P_s= 500kpa[/tex]
Valve final pressure [tex]P_v=500kpa[/tex]
Piston movement pressure [tex]P_m=200kpa[/tex]
Piston-cylinder final Volume of air[tex]v_2=0.2 m^3[/tex]
Piston-cylinder final temperature [tex]T_2=440k[/tex]
Piston-cylinder final pressure [tex]P_2= 500kpa[/tex]
Generally the equation for conservation of mass is mathematically given by
[tex]Q=m_2 \mu_2-m_1 \mu_1 +W-(m_2-m_1)h[/tex]
where
Initial moment
[tex]m_1=\frac{p_1 V_1}{RT_1}[/tex]
[tex]m_1=\frac{100*0.1}{0.287*400}[/tex]
[tex]m_1=8.7*10^-^2kg[/tex]
Final moment
[tex]m_2=\frac{p_2 V_2}{RT_2}[/tex]
[tex]m_1=\frac{500*0.3}{0.287*440}[/tex]
[tex]m_1=79*10^{-2}kg[/tex]
Work done by Piston movement pressure
[tex]W=Pd[/tex]
[tex]W=P(v_2-v_1)[/tex]
[tex]W=200(0.2-0.1))[/tex]
[tex]W=20000J[/tex]
Heat function
[tex]h=cT_1[/tex]
[tex]h=1.005(400)[/tex]
[tex]h=402[/tex]
Therefore
[tex]Q=(0.792*0.718(440)-0.0871*0.718(400)+20-(0.792-0.087)*402))[/tex]
[tex]Q=-38.15kJ[/tex]
It is given mathematically that the system lost or dissipated Heat of
[tex]Q=-38.15kJ[/tex]
An incident ray that passes through the vertex of a convex lens:
F
F
c
A. refracts inward, at an angle equal to the angle of incidence,
B. continues in a straight line without refracting.
C. refracts parallel to the axis of the lens,
D. refracts outward, at an angle equal to the angle of incidence.