Answers
Answer:
[tex]\tan A=\frac{10}{24}=\frac{5}{12}[/tex]
Step-by-step explanation:
The easiest way to remember sine, cosine, and tangent ratios is to use SOH-CAH-TOA as an acronym.
SOH - Sine: Opposite over hypotenuse
CAH - Cosine: Adjacent over hypotenuse
TOA - Tangent: Opposite over adjacent
Note that these are referring to the position of the sides relative to the angle you are looking at. In this case, that is angle A. Since it's tangent, we have:
[tex]\tan A=\frac{10}{24}=\frac{5}{12}[/tex]
Related Questions
A lottery game has balls numbered 1 through 21. What is the probability of selecting an even numbered ball or an 8? Round to nearest thousandth
Answers
Answer: 0.476
Step-by-step explanation:
Let A = Event of choosing an even number ball.
B = Event of choosing an 8 .
Given, A lottery game has balls numbered 1 through 21.
Sample space: S= {1,2,3,4,5,6,7,8,...., 21}
n(S) = 21
Then, A= {2,4,6,8, 10,...(20)}
i.e. n(A)= 10
B= {8}
n(B) = 1
A∪B = {2,4,6,8, 10,...(20)} = A
n(A∪B)=10
Now, the probability of selecting an even numbered ball or an 8 is
[tex]P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}[/tex]
[tex]=\dfrac{10}{21}\approx0.476[/tex]
Hence, the required probability =0.476
WILL MARK AS BRAINLIEST 4. Suppose there is a card game where you are dealt a hand of three cards. You have already learned that the total number of three-card hands that can be dealt from a deck of 52 cards is: 52C3=52!/49!3! 52C3=22100 Calculate the probability of getting a hand that has exactly two aces in it (A A X). Do this by finding out the number of possible hands that have exactly two aces, and then dividing by the total possible number of three-card hands that is stated above. Part A: Use the multiplication principle to tell the total number of three-card hands (permutations) that can be made with two aces. (2 points) Part B: In the answer from Part I, each two-ace hand got counted twice. For example, A A X got counted as a separate hand from A A X. Since order should not matter in a card hand, these are really the same hand. What is the actual number of two-ace hands (combinations) you can get from a deck of 52 cards?(2 points) Part C: Find the probability of drawing a three-card hand that includes two aces from a deck of 52 cards. Write your answer as a fraction. (2 points)
Answers
Answer:
Part A- 6
Part B- 3
Part C- 3/22100
Step-by-step explanation:
Part A-
Use the permutation formula and plug in 3 for n and 2 for k.
nPr=n!/(n-k)!
3P2=3!/(3-2)!
Simplify.
3P2=3!/1!
3P2=6
Part B-
Use the combination formula and plug in 3 for n and 2 for k.
nCk=n!/k!(n-k)!
3C2=3!/2!(3-2)!
Simplify.
3C2=3!/2!(1!)
3C2=3
Part C-
It is given that the total number of three-card hands that can be dealt from a deck of 52 cards is 22100. Use the fact that the probability of something equals the total successful outcomes over the sample space. In this case the total successful outcomes is 3 and the sample space is 22100.
I believe the answer is 3/22100
I honestly suck at probability but I tried my best.
Help ASAP - Find the area of the composite figure made up of a square and a semicircle. Use 3.14 as an approximation for and give your
answer to the nearest square inch. Enter only the number.
Answers
Answer:
200.52 in^2
Step-by-step explanation:
to find the area of a circle, you square 6 and multiply it by pi in this case 3.14.
that gives you 113.04 but because this is only a half circle, it is 56.52 in^2.
Next, you need to find the rectangle. multiply 12(length) by 12(Width) to get 144 add 144 to 56.52 to get 200.52.
Hope this helped if it did please give me brainliest it helps me a lot. :)
Have a good day!
All sides of the building shown above meet at right angles. If three of the sides measure 2 meters, 7 meters, and 11 meters as shown, then what is the perimeter of the building in meters?
Answers
Answer:
Perimeter= 40 units
Step-by-step explanation:
Ok
We are asked to look for the perimeter.
We have some clue given.
All at right angle and some sides are given it's full length.
We have the bae to be 11 unit
The height to be 7 unit.
What this mean is that taking either the base or the height should sum up to either 11 or 7 respectively.
Let's go for the other side of the height.
Let's take all the vertical height and sum it up to 7 because the right side is equal to 7.
So we have 7+7+11
But it's not complete yet.
We are given a dimension 2.
And the 2 is in two places so it's total 2*2= 4
The two is for a small base .
The base is actually an extra to the 11 of the other base.
So summing up
We have 2*11 + 2*7 + 2*2
Perimeter= 22+14+4
Perimeter= 40 units
I need help with this !!
Answers
Answer:
A
Step-by-step explanation:
When subtracting 7 on the left of the equation, he also needs to subtract 7 from the right of the equation.
Step 2 should be:
⅓X +7 -7= 15 -7
What he is trying to do here by subtracting 7 is to move all the constants, that is numbers without any variables such as x, to one side of the equation.
⅓X= 8
X= 8 ×3
X= 24
2) A basketball player scores 70% of his shots on average. What is the probability that he scores at least 18 successful shots tonight if he gets 20 shots?
Answers
Answer:
3.54%
Step-by-step explanation:
This question represents a binomial distribution. A binomial distribution is given by:
[tex]P(x)=\frac{n!}{(n-x)!x!} p^xq^{n-x}[/tex]
Where n is the total number of trials, p is the probability of success, q is the probability of failure and x is the number of success.
Given that:
A basketball player scores 70% of his shots on average, therefore p = 70% = 0.7. Also q = 1 - p = 1 - 0.7 = 0.3.
The total number of trials (n) = 20 shots
The probability that he scores at least 18 successful shots tonight if he gets 20 shots = P(x = 18) + P(x = 19) + P(x = 20)
P(x = 18) = [tex]\frac{20!}{(20-18)!18!}*0.7^{18}*0.3^{20-18}=0.0278[/tex]
P(x = 19) = [tex]\frac{20!}{(20-19)!19!}*0.7^{19}*0.3^{20-19}=0.0068[/tex]
P(x = 20) = [tex]\frac{20!}{(20-20)!20!}*0.7^{20}*0.3^{20-20}=0.0008[/tex]
The probability that he scores at least 18 successful shots tonight if he gets 20 shots = P(x = 18) + P(x = 19) + P(x = 20) = 0.0278 + 0.0068 + 0.0008 = 0.0354 = 3.54%
Translate this sentence into an equation. 59 is the sum of 11 and Mai’s score
Answers
Answer:
11 + Mai's Score = 59
Step-by-step explanation:
You need to add 11 and Mai's score together to get 59, so with the values given we can make the equation 11 + Mai's Score = 59.
*depending on the question, Mai's score may need to be said as a letter variable, so:
If m = mai's score,
11 + m = 59
I hope this helped! :)
i give you a tricky one Express 108 ×125as a product of prime factors in exponential form
Answers
Answer:
[tex]108 \times 125=2^2 \times 3^3 \times 5^3[/tex]
Step-by-step explanation:
To express the given product (108 X 125) as a product of prime factors
Step 1: Express each of the numbers as a product of its prime factors.
[tex]108=2^2 \times 3^3\\125=5^3[/tex]
Step 2: Write the product together, and combine any like terms if any
Therefore,
[tex]108 \times 125=2^2 \times 3^3 \times 5^3[/tex]
Copy the problem, mark the givens in the diagram. Given: CS ≅ HR, ∠CHS ≅ ∠HCR, ∠CSH ≅ ∠HRC, Prove: CR ≅ HS
Help urgently needed
Answers
Explanation:
1. CS ≅ HR, ∠CHS ≅ ∠HCR, ∠CSH ≅ ∠HRC — given
2. ∆CRH ~ ∆HSC — AA similarity theorem
3. ∠SCH ≅ ∠RHC — corresponding angles of similar triangles are congruent
4. CH ≅ HC — reflexive property of congruence
5. ∆CRH ≅ ∆HSC — SAS congruence theorem
6. CR ≅ HS — CPCTC
The cost of plastering the 4 walls of a room which is 4m high and breadth one third of its length is Rs. 640 at the rate of Rs. 5/m². What will be the cost of carpeting its floor at the rate of Rs. 250/m².
Answers
Answer:
Rs. 32,000
Step-by-step explanation:
height = 4m
let length = x m
breadth = x/3 m
Area of the 4 walls = 2(length × height) + 2(breadth × height)
Area = 2(4×x) + 2(4 × x/3) = 8x + (8x)/3
Area = (32x)/3 m²
1 m² = Rs. 5
The cost for an area that is (32x)/3 m²= (32x)/3 × 5 Rs.
The cost of plastering 4 walls at Rs.5 per m² = 640
(32x)/3 × 5 = 640
(160x)/3 = 640
x = length = 12
Area = (32x)/3 m² = (32×12)/3 = 128m²
The cost of carpeting its floor at the rate of Rs. 250/m²:
= 128m² × Rs. 250/m² = 32,000
The cost of carpeting its floor at the rate of Rs. 250/m² = Rs. 32,000
Find the largest integer which belongs to the following interval: [−∞, 31]
Answers
Answer:
Largest integer in the interval [−∞, 31] is 31.
Step-by-step explanation:
Given the interval: [−∞, 31]
To find: The largest integer in this interval.
Solution:
First of all, let us learn about the representation of intervals.
Two kind of brackets can be used to represent the intervals. i.e. () and [].
Round bracket means not included in the interval and square bracket means included in the interval.
Also, any combination can also be used.
Let us discuss one by one.
1. [p, q] It means the interval contains the values between p and q. Furthermore, p and q are also included in the interval.
Smallest p
Largest q
2. (p, q) It means the interval contains the values between p and q. Furthermore, p and q are not included in the interval.
Smallest value just greater than p.
Largest value just smaller than q.
3. [p, q) It means the interval contains the values between p and q. Furthermore, p is included in the interval but q is not included in the interval.
Smallest value p.
Largest value just smaller than q.
4. (p, q] It means the interval contains the values between p and q. Furthermore, p is not included in the interval but q is included in the interval.
Smallest value just greater than p.
Largest value q.
As per above explanation, we can clearly observe that:
The largest integer which belongs to the following interval: [−∞, 31] is 31.
For questions 13-15, Let Z1=2(cos(pi/5)+i Sin(pi/5)) And Z2=8(cos(7pi/6)+i Sin(7pi/6)). Calculate The Following Keeping Your Answer In Polar Form. 13. z1z2 14. z2 15. z1/z2
Answers
Answer:
Step-by-step explanation:
Given the following complex values Z₁=2(cos(π/5)+i Sin(πi/5)) And Z₂=8(cos(7π/6)+i Sin(7π/6)). We are to calculate the following complex numbers;
a) Z₁Z₂ = 2(cos(π/5)+i Sin(πi/5)) * 8(cos(7π/6)+i Sin(7π/6))
Z₁Z₂ = 18 {(cos(π/5)+i Sin(π/5))*(cos(7π/6)+i Sin(7π/6)) }
Z₁Z₂ = 18{cos(π/5)cos(7π/6) + icos(π/5)sin(7π/6)+i Sin(π/5)cos(7π/6)+i²Sin(π/5)Sin(7π/6)) }
since i² = -1
Z₁Z₂ = 18{cos(π/5)cos(7π/6) + icos(π/5)sin(7π/6)+i Sin(π/5)cos(7π/6)-Sin(π/5)Sin(7π/6)) }
Z₁Z₂ = 18{cos(π/5)cos(7π/6) -Sin(π/5)Sin(7π/6) + i(cos(π/5)sin(7π/6)+ Sin(π/5)cos(7π/6)) }
From trigonometry identity, cos(A+B) = cosAcosB - sinAsinB and sin(A+B) = sinAcosB + cosAsinB
The equation becomes
= 18{cos(π/5+7π/6) + isin(π/5+7π/6)) }
= 18{cos((6π+35π)/30) + isin(6π+35π)/30)) }
= 18{cos((41π)/30) + isin(41π)/30)) }
b) z2 value has already been given in polar form and it is equivalent to 8(cos(7pi/6)+i Sin(7pi/6))
c) for z1/z2 = 2(cos(pi/5)+i Sin(pi/5))/8(cos(7pi/6)+i Sin(7pi/6))
let A = pi/5 and B = 7pi/6
z1/z2 = 2(cos(A)+i Sin(A))/8(cos(B)+i Sin(B))
On rationalizing we will have;
= 2(cos(A)+i Sin(A))/8(cos(B)+i Sin(B)) * 8(cos(B)-i Sin(B))/8(cos(B)-i Sin(B))
= 16{cosAcosB-icosAsinB+isinAcosB-sinAsinB}/64{cos²B+sin²B}
= 16{cosAcosB-sinAsinB-i(cosAsinB-sinAcosB)}/64{cos²B+sin²B}
From trigonometry identity; cos²B+sin²B = 1
= 16{cos(A+ B)-i(sin(A+B)}/64
= 16{cos(pi/5+ 7pi/6)-i(sin(pi/5+7pi/6)}/64
= 16{ (cos 41π/30)-isin(41π/30)}/64
Z1/Z2 = (cos 41π/30)-isin(41π/30)/4
Answer:
13. 16(cos(41 π/30)+ isin(41 π/30))
14. Mine asked for z2 magnitude so I got 8 (magnitude is the same as modulus which is r)
15. 1/8 (cos(29 π/30)+ isin(29 π/30))
Step-by-step explanation:
13. Since we’re multiplying z1, and z2, use De Moivre’s theorem by multiplying the r values (2 and 8) and adding the theta values (π/5 and 7π/6). Adding the angle values should lead you to have 41 π/30, and the rest is self-explanatory.
14. Explanation is in the answer, just take the r value from z2 for magnitude (at least that’s what’s on my practice assignment)
15. Use De Moivre’s theorem again, this time with division, so you will divide the r values (2 divided by 8) and subtract the theta values (π/5 minus 7π/6). 2/8 simplifies to 1/8 and when subtracting with 6π/30 - 35π/30 (finding common denominators) you should get 29π/30.
Is 3 a solution to the equation 6x – 7 = 12?
Answers
Answer:
3 is not a solution
Step-by-step explanation:
6x – 7 = 12?
Substitute 3 in for x and see if the equation is true
6*3 - 7 = 12
18-7 = 12
11 =12
This is false so 3 is not a solution
6x = 12 +7
6x = 19
x = 19 / 6
x = 3.2 (1 dp)
I HOPE THIS HELPS:)
A circle is centered at CC-1, -3) and has a radius of 6.
Where does the point P(-6, -6) lie?
Choose 1 answer:
Inside the circle
On the circle
Outside the circle
Answers
Answer:
outside the circle i think
Step-by-step explanation:
Answer:
inside the circle
Step-by-step explanation:
SOMEONE PLEASE HELP ME!!! I REALLY NEED SOME HELP!!!
Which of the following points is a solution of the inequality y < - lxl?
A. (1, -2)
B. (1, -1)
C. (1, 0)
Answers
Answer:
A. (1, -2)
Step-by-step explanation:
We can substitute the variables of x and y into the inequality of [tex]y < -|x|[/tex].
Let's start with A, -2 being y and 1 being x.
[tex]-2 < - |1|[/tex]
The absolute value of 1 is 1, and negating that gets us -1.
[tex]-2 < -1[/tex]
Indeed, -2 is less than -1! So A is a solution to the inequality.
Let's test the rest of them, just in case.
For B:
[tex]-1 < -|1|[/tex]
Absolute value of 1 is 1, negating it is -1.
[tex]-1<-1[/tex]
-1 is EQUAL to -1, not less than it, so is not a solution to the inequality.
Let's try C.
[tex]0 < -|1|[/tex]
Absolute value of 1 is 1, negating it is -1.
[tex]0 < -1[/tex]
0 is GREATER than -1, so that is not a solution to the inequality.
Hope this helped!
Good evening can I get help please?
Answers
Answer:
Yes.
Step-by-step explanation:
1+1=2
3+5=8
7+1=8
9+23=32
5+13=18
An odd number is an even number plus 1, and 1 plus 1 is an even number. even numbers added together are also always even numbers, so two even numbers (in the second example it'd be 2+1 & 4+1, so 2 and 4) plus an even number(1+1=2) must be an even number.
Which sequence of transformations on preimage Triangle ABC will NOT produce the image A’B’C’
Answers
Answer:
b
Step-by-step explanation:
Need Answers ASAP!!!!
Answers
Answer:
15.9degrees
Step-by-step explanation:
in photo above
Answer:
[tex]\boxed{15.95\°}[/tex]
Step-by-step explanation:
The angle can be found by using trigonometric functions.
tan (θ) = [tex]\frac{opposite}{adjacent}[/tex]
tan (θ) = [tex]\frac{4}{14}[/tex]
θ = [tex]tan^{-1} \frac{4}{14}[/tex]
θ = 15.9453959
θ ≈ 15.95
Use the interactive number line to find the difference. 4.7 - 2.3 = 4.7 + (-2.3) =
Answers
Answer:
Arrow from 0 to 4.7 and from 4.7 to 2.4
Step-by-step explanation:
4.7 is also 0+4.7
arrow from 0 to 4.7.
-2.3 from 4.7 is 4.7-2.3=2.4
arrow from 4.7 to 2.4.
Answer:
Use the interactive number line to find the difference.
4.7 - 2.3 = 4.7 + (-2.3) =
✔ 2.4
Step-by-step explanation:
need help thanksssssssss
Answers
Answer:
Volume: 112 m³.
Surface area: 172 m².
Step-by-step explanation:
The volume is the base times height times length. So, the volume will be 2 * 8 * 7 = 16 * 7 = 112 m³.
The surface area is 2lw + 2lh + 2wh. l = 8; w = 7; h = 2.
2(8)(7) + 2(8)(2) + 2(7)(2) = 2 * 56 + 2 * 16 + 2 * 14 = 112 + 32 + 28 = 112 + 60 = 172 m².
Hope this helps!
Find the slope of the line passing through the points (-3, -8) and (4,6).
Answers
Answer:
slope = 2Step-by-step explanation:
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have
[tex](-3;\ -8)\to x_1=-3;\ y_1=-8\\(4;\ 6)\to x_2=4;\ y_2=6[/tex]
Substitute:
[tex]m=\dfrac{6-(-8)}{4-(-3)}=\dfrac{6+8}{4+3}=\dfrac{14}{7}=2[/tex]
The formula for the slope m of the line that passes through two points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is the following:
[tex]m=\dfrac{y_1-y_2}{x_1-x_2}[/tex]
We have points (4,6) and (-3,-8). Let's plug these values into the formula for slope:
[tex]m=\dfrac{6-(-8)}{4-(-3)}[/tex]
[tex]=\dfrac{14}{7}=2[/tex]
The slope of the line passing through the two points is 2. Let me know if you need any clarifications, thanks!
25 points will mark brainlest as part of the save nature campaign the city Forest department has decided to grow more trees to kick off the campaign they start by planting 2 pine trees it has been decided that every year they will increase the amount of trees but 1 tree less than the square of the previous year's count which of the following recursives formulas can be used to determine the total number of tree planted in the future assume there is in limited space for trees and n is the number of years of the program's operation
Answers
Answer:
N(n+1) = N(n)^2 - 1, n>=0, N(0) = 2
or equivalently
N(n) = N(n-1)^2 - 1, n>0, N(0) = 2
Step-by-step explanation:
Year 0 = 2 trees
year 1 = 2^2-1 = 3
year 2 = 3^2-1 =8
year 2 = 8^2-1 =63
...
Recursive formula
Let
n = integer year number
N(n) = number of trees to plant in year n
N(n+1) = N(n)^2-1, n>=0, N(0) = 2
or equivalently
N(n) = N(n-1)^2, n>0, N(0) = 2
Whats the options???
How many real roots and how many complex roots exist for the polynomial
F(x) - X4+ x2 - 5x2 + x -- 6?
O A. 2 real roots and 2 complex roots
B. O real roots and 4 complex roots
O c. 3 real roots and 1 complex root
D. 4 real roots and 0 complex roots
Answers
Answer:
D. 4 real roots and 0 complex roots
Step-by-step explanation:
If I assume that the function you are saying is
[tex]F(x)=x^4+x^3-5x^2+x-6[/tex]
There should be up to "4 roots," there can't be more or less than 4 total solutions. First, we need to check how many sign changes are there in this function. There are 3 positive real roots. Now lets check for negative roots.
[tex]F(-x)=x^4-x^3-5x^2-x-6[/tex]
There are is only 1 negative real root. Since we basically have 4 real roots, and the max is 4. There should be 4 real roots and 0 complex roots.
The value of a car dropped from $7400 to $6800 over the last year. What percent decrease is this?
Answers
Answer:
8.1% decrease
Step by step
To find precentage decrease we use formula:
Percent decrease= original amount-new amount/original amount(100%)
percent decrease= 7,400-6,800/7,400(100%)=300/37=8.1%
How to calculate a circumference of a circle?
Answers
Answer: Pi multiplied by the diameter of the circle
Step-by-step explanation:
Answer:
The formula for finding the circumference of a circle is [tex]C = 2\pi r[/tex]. You substitute the radius of the circle for [tex]r[/tex] and multiply it by [tex]2\pi[/tex].
*4.8.21
Question Help
O
After the release of radioactive material into the atmosphere from a nuclear power plant in a country in 2000, the hay in that country was contaminated by a radioactive
isotope (half-life 7 days). If it is safe to feed the hay to cows when 14% of the radioactive isotope remains, how long did the farmers need to wait to use this hay?
The farmers needed to wait approximately days for it to be safe to feed the hay to the cows.
(Round to one decimal place as needed.)
ות
nts
Enter your answer in the answer box and then click Check Answer.
All parts showing
Clear All
Check Answer
OK
here to search
O
Answers
Answer:
19.9 days
Step-by-step explanation:
The amount remaining after d days is ...
a = (1/2)^(d/7)
We want to find d when a = 0.14
log(a) = (d/7)log(1/2)
d = 7·log(0.14)/log(1/2) ≈ 19.855 ≈ 19.9
The farmers need to wait about 19.9 days for it to be safe.
The solutions to the inequality ys-x+1 are shaded on
the graph. Which point is a solution?
(2, 3)
(3,-2)
(2.1)
(-1,3)
Answers
Answer:
the solutions to the inequality ys-x+1 are shaded on the graph. which point is B. (3 ,-2)
What is the measure of x?
Answers
Answer:
9 in.
Step-by-step explanation:
Given that the line 10 in. and line 4 in. are parallel, then the two triangles are similar.
As such, the ratio of the sides would give the same results.
Hence,
4/6 = 10/(6 + x)
cross multiplying
4(6 + x) = 60
Dividing both sides by 4
6 + x = 15
collecting like terms
x = 15 - 6
= 9
Mai invests $20,000 at age 20. She hopes the investment will be worth $500,000 when she turns 40. If the interest compounds continuously, approximately what rate of growth will she need to achieve her goal? Round to the nearest tenth of a percent.
Answers
Answer:16.1%
Step-by-step explanation:
Answer:
The investment needs the rate of growth to be approximately 16.1%.
Step-by-step explanation:
Please help
ASAP
ANSWERS
A-48.21
B-66.35
C-53.68
D-28.34
Answers
Answer:
B
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos54° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{39}{AB}[/tex] ( multiply both sides by AB )
AB × cos54° = 39 ( divide both sides by cos54° )
AB = [tex]\frac{39}{cos54}[/tex] ≈ 66.35 → B