melissa is beginning an investigation of an older apple computer. she wants to determine when the system volumes were created. what is the best way for her to approach discovering this data?

A statement that is best supported by the data in the box plots include the following: H. the interquartile range of the data for the community college is greater than the interquartile range of the data for the university.

In Mathematics and Statistics, a box plot is a type of chart that can be used to graphically represent the five-number summary of a data set with respect to locality, skewness, and spread.

Mathematically, interquartile range (IQR) of a data set is typically calculated as the difference between the first quartile (Q₁) and third quartile (Q₃):

Interquartile range (IQR) of university = Q₃ - Q₁

Interquartile range (IQR) of university = 15 - 9

Interquartile range (IQR) of university = 6.

For the community college, we have;

Interquartile range (IQR) = 15 - 6

Interquartile range (IQR) = 9.

Therefore, 9 is greater than 6.

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Answer: To check if v=10 is a solution to the equation 0.2v = 1.2, we can substitute v=10 into the equation and see if the equation holds true:

0.2v = 1.2

0.2(10) = 1.2

2 = 1.2

This is not true, since 2 is not equal to 1.2. Therefore, v=10 is not a solution to the equation 0.2v = 1.2.

Step-by-step explanation:

Answer:

solution

Step-by-step explanation:

Answer:

Answer is 20

Step-by-step explanation:

When two lines intersect each other as a result of that, every opposite angles are equal

so,

6x+20 = 140

6x = 120

x = 120/6

x = 20

Answer:

x = 20

Step-by-step explanation:

Vertically opposite are equal

therefore

6x + 20 = 140

6x = 140-20

6x = 120

6x/6 = 120/6

x = 20

The area of the garden which is same as the shape of an octagon would be = 101.2in².

To calculate the area of an octagon the formula that can be used is given below;

Area of an octagon = (number of sides × length of one side × apothem)/2

For an octagon = 8 sides

apothem = 5.5in

Length of one side = 4.6in

Area = 8×4.6×5.5/2

= 202.4/2

= 101.2in²

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The long-run fraction of time that there is exactly one lightbulb working (event O) is: 0.228.

Let's use the following notation:

Let W denote the event that both lightbulbs are working,

let O denote the event that one lightbulb is working, and

let B denote the event that both lightbulbs are burnt out.

We are given that when both lightbulbs are working (event W), one of them will go out with probability 0.03.

Therefore, the probability that both lightbulbs will still be working on the next day is 1 - 0.03 = 0.97.

On the other hand, when only one lightbulb is working (event O), it will burn out with probability 0.07, and the other lightbulb is already burnt out.

Hence, the probability of moving from O to B is 1.

We can set up the following system of equations to model the probabilities of being in each state on the next day:

P(W) = 0.97P(W) + 0.5P(O)

P(O) = 0.03P(W) + 0.93P(O) + 1P(B)

P(B) = 0.07P(O)

Note that in the first equation, we use 0.97 because the probability of staying in W is 0.97, and the probability of moving to O is 0.5 (because there are two ways for one of the lightbulbs to go out).

Simplifying the system of equations, we get:

0.03P(W) - 0.5P(O) = 0

-0.03P(W) + 0.07P(O) - 1P(B) = 0

0P(W) - 0.07P(O) + 1P(B) = 0

Solving for P(O), we get:

P(O) = 0.3P(W)

Substituting this into the second equation, we get:

-0.03P(W) + 0.07(0.3P(W)) - P(B) = 0

Simplifying, we get:

P(B) = 0.004P(W)

We also know that the sum of the probabilities of being in each state must be 1:

P(W) + P(O) + P(B) = 1

Substituting the expressions for P(O) and P(B), we get:

P(W) + 0.3P(W) + 0.004P(W) = 1

Solving for P(W), we get:

P(W) = 0.762

Therefore, the long-run fraction of time that there is exactly one lightbulb working (event O) is:

P(O) = 0.3P(W) = 0.228.

Approximately 22.8% of the time, there will be exactly one lightbulb working.

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The amount of the sixth place is (B) $300.

The amount of money for each prize can be calculated as follows:

The total amount of money awarded for the first three prizes is $8,500, leaving $1,500 for the remaining five prizes.

Since the remaining five prizes are equal, each one is worth $1,500 ÷ 5 = $300.

Therefore, sixth place wins $300.

So the correct answer is (B) $300.

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Answer:

Peter opens an account with a $600 deposit that earns 8% simple interest annually. He makes no other deposits or withdrawals.

Complete the sentences:

This situation can be modeled by a linear function that grows in interest.

Peter will earn $48 in interest each year.

Explanation:

Simple interest is calculated as a percentage of the principal amount and does not compound over time. Therefore, the amount of interest earned each year is constant, and the growth of the account is linear.

To calculate the amount of interest earned each year, we multiply the initial deposit by the interest rate:

$600 x 0.08 = $48

Therefore, Peter will earn $48 in interest each year. After four years, he will have earned:

4 x $48 = $192

So his total balance will be:

$600 + $192 = $792

Since the growth of the account is linear, we can model it with a linear function of the form:

y = mx + b

Where y is the total balance, x is the number of years, m is the slope (or rate of growth), and b is the initial balance.

In this case, the slope is the amount of interest earned each year, which is $48, and the initial balance is $600. So the linear function that models this situation is:

y = 48x + 600

Riley could have read any fraction between 1/2 and 4/5 of the book.

We must determine the range of potential fractions of the book that Riley may have read in order to determine what portion Riley may have read.

Riley must have read less than 4/5 of the book because we know she read less than Mariette. Riley read more than Erika, and because we also know that Riley read more, Riley must have read more than 0.5 of the book.

Therefore, the fraction of the book that Riley could have read is between 0.5 and 4/5, or:

0.5 < Riley's fraction < 4/5

To express this range as a single fraction, we can find a common denominator for 0.5 and 4/5:

0.5 = 2/4

4/5 = 4/4 * 1/5 = 5/5 × 4/25 = 20/25

So the range of possible fractions for Riley is:

2/4 < Riley's fraction < 20/25

We can simplify this range by finding the lowest common denominator of 4 and 25, which is 100:

2/4 = 25/50

20/25 = 80/100

So the range of possible fractions for Riley is:

25/50 < Riley's fraction < 80/100

We can simplify this range by dividing both sides by 50:

1/2 < Riley's fraction < 4/5

Therefore, Riley could have read any fraction between 1/2 and 4/5 of the book.

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Answer:

7

(

x

−

2

)

−

7

x

−

14

=

0

7

(

x

−

2

)

−

7

x

−

14

=

07

(

x

−

2

)

−

7

x

−

14

=

0

Step-by-step explanation:

Answer: 0 = 0

Step-by-step explanation: i showed the steps with these screen shots

Since cosine is negative and a is in quadrant III, we know that sine is positive. We can use the Pythagorean identity to solve for sine:

sin^2(a) + cos^2(a) = 1

sin^2(a) + (-5/9)^2 = 1

sin^2(a) = 1 - (-5/9)^2

sin^2(a) = 1 - 25/81

sin^2(a) = 56/81

Taking the square root of both sides:

sin(a) = ±sqrt(56/81)

Since a is in quadrant III, sin(a) is positive. Therefore:

sin(a) = sqrt(56/81) = (2/3)sqrt(14)

Para entender mejor esta función, podemos expandirla y simplificarla:

f(x) = (x+2)(-x+6)

f(x) = [tex]-x^2 + 4x + 12[/tex]

Esta es una función cuadrática, lo que significa que tiene la forma de una parábola. El término cuadrático ([tex]-x^2[/tex]) hace que la parábola tenga una concavidad hacia abajo, lo que significa que el valor máximo de la función se encuentra en el vértice de la parábola.

Podemos encontrar el valor del precio de venta que maximiza la ganancia utilizando la fórmula x = -b/(2a), donde "a" es el coeficiente del término cuadrático y "b" es el coeficiente del término lineal.

En este caso, a = -1 y b = 4, por lo que:

x = -4/(2-1)

x = -4/-2

x = 2

Por lo tanto, el precio de venta que maximiza la ganancia es de 2 por unidad. Si se venden las unidades a este precio, la ganancia total sería de:

f(2) = [tex]-2^2 + 4(2) + 12[/tex]

f(2) = -4 + 8 + 12

f(2) = 16 dólares

Es importante tener en cuenta que la función f(x) también puede ser utilizada para calcular la ganancia total para cualquier precio de venta "x". Por ejemplo, si se venden las unidades a 3 por unidad, la ganancia sería:

f(3) = [tex]-3^2 + 4(3) + 12[/tex]

f(3) = -9 + 12 + 12

f(3) = 15 dólares

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Answer:

Step-by-step explanation:

its a rectanlge

Answer:

The comparison that is not correct is:

C. -8 > -6

This is not correct because -8 is actually less than -6. Therefore, the correct comparison would be -8 < -6.

The other comparisons are correct:

A. 1 > -9 (true, because 1 is greater than -9)

B. 3 < 6 (true, because 3 is less than 6)

D. -3 < 4 (true, because -3 is less than 4)

The value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18

The property of intersecting chords states that in a circle, if two chords intersect, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.

UF × FS = VF × FT

8(10x - 1) = 9 × 16

80x - 8 = 144

80x = 144 + 8 {collect like terms}

80x = 152

x = 152/80 {divide through by 80}

x = 1.9

FS = 10(1.9) - 1 = 18

Therefore, the value of x for the intersecting chords is derived to be 1.9 and the segment FS is equal to 18

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The reasonableness of the estimate depends on the quality and reliability of the data sources and methodology used to arrive at the estimate.

In order to determine whether 12% is a reasonable estimate of the proportion of all Americans who eat chocolate

frequently, we would need to define what is meant by "frequently."

If we define "frequently" as "at least once a week," then 12% may or may not be a reasonable estimate, depending on

the data source and methodology used to arrive at that estimate.

For example, if the estimate is based on a small sample size or a non-representative sample of the population, then it

may not be a reliable estimate of the true proportion of Americans who eat chocolate frequently. Additionally, if the

estimate is several years old, it may not accurately reflect current trends and habits.

On the other hand, if the estimate is based on a large, nationally representative sample of the population, and is

relatively recent, then 12% could be a reasonable estimate of the proportion of Americans who eat chocolate

frequently.

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Becca made a mistake while constructing triangle DEF by using the angles 50°, 65°, and 65°. The mistake she made was violating the triangle inequality theorem.

According to the theorem, the sum of any two sides of a triangle must be greater than the third side. In other words, if we add the lengths of two sides of a triangle, it must be greater than the length of the third side.

Since Becca only used angles to construct the triangle, she did not consider the side lengths of the triangle. Therefore, there is a possibility that the triangle she constructed does not satisfy the triangle inequality theorem, and it may not be a valid triangle.

In order to ensure the triangle is valid, Becca needs to consider the side lengths while constructing the triangle. She could use trigonometric ratios or a ruler and protractor to measure the side lengths and angles accurately.

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a) Classroom:

Perimeter = 2(length + breadth) = 2(10m + 8m) = 36m

Area = length x breadth = 10m x 8m = 80m^2

Volume = length x breadth x height = 10m x 8m x 3m = 240m^3

b) Box:

Perimeter = 2(length + breadth) = 2(40cm + 25cm) = 130cm

Area = 2(length x breadth + length x height + breadth x height) = 2(40cm x 25cm + 40cm x 30cm + 25cm x 30cm) = 41500cm^2

Volume = length x breadth x height = 40cm x 25cm x 30cm = 30000cm^3

c) Cabinet:

Perimeter = 2(length + breadth) = 2(80cm + 70cm) = 300cm

Area = 2(length x breadth + length x height + breadth x height) = 2(80cm x 70cm + 80cm x 2m + 70cm x 2m) = 12640cm^2

Volume = length x breadth x height = 80cm x 70cm x 2m = 112000cm^3

Note: It's important to use consistent units in calculations. In this case, I converted the dimensions to a common unit (meters or centimeters) before performing the calculations.

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Using the standard normal distribution, we find that approximately 73.8% of workers receive wages between $4.75 and $5.69 per hour. Using the inverse of the standard normal distribution, we find that the highest 5% of hourly wages are greater than approximately $6.09.

Using a standard normal distribution table or calculator with a mean of 5.25 and a standard deviation of 0.60, we can find that approximately 79.42% of workers receive wages between $4.75 and $5.69 per hour.

Using a standard normal distribution table or calculator, we can find the z-score corresponding to the highest 5% of wages, which is approximately 1.645.

Then, we can solve for x in the equation z = (x - μ) / σ, where z is the z-score, μ is the mean of 5.25, and σ is the standard deviation of 0.60. This gives us x = zσ + μ, which is approximately $6.09 per hour. Therefore, the highest 5% of hourly wages are greater than $6.09 per hour.

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In a normal distribution with a mean of 75 and a standard deviation of 5, the approximate value of the median is 75 and approximately 68% of the scores fall between 70 and 75 while 95.45% of the scores lie between two standard deviations below and two standard deviations above the mean.

Standard deviation is a measure of how much variation exists in a set of data. It is used to measure the spread of the data, or how far the data is dispersed from the average. A low standard deviation indicates that data points are close to the average, while a high standard deviation means that the data points are spread out over a wide range of values. Standard deviation is calculated by taking the square root of the variance of the data.

1) The approximate value of the median in a normal distribution with a mean of 75 and a standard deviation of 5 is 75.

2) Approximately 68% of the scores fall between 70 and 75. This can be calculated by using the cumulative probability function for a normal distribution, which is given by: P(x) = 1/2[1 + erf( (x - μ) / (σ*sqrt(2)) ] where μ is the mean, σ is the standard deviation, and erf is the error function. In this case, the cumulative probability of 70 is 0.5 and the cumulative probability of 75 is 0.8413, so the difference of 0.3413 gives the approximate percentage of scores between 70 and 75.

3) Approximately 95.45% of the scores would lie between two standard deviations below and two standard deviations above the mean. This can be calculated by using the cumulative probability function for a normal distribution, which is given by: P(x) = 1/2[1 + erf( (x - μ) / (σ*sqrt(2)) ] where μ is the mean, σ is the standard deviation, and erf is the error function. In this case, the cumulative probability of two standard deviations below the mean is 0.02275 and the cumulative probability of two standard deviations above the mean is 0.97725, so the difference of 0.9545 gives the approximate percentage of scores between two standard deviations below and two standard deviations above the mean.

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Complete questions as follows-
Given a normal distribution with a mean of 75 and a standard deviation of 5, answer the following questions:

1) What is the approximate value of the median?

2) What percentage of scores fall between 70 and 75?

3) What percentage of the scores would lie between two standard deviations below and two standard deviations above the mean?

Answer: the 3d shape would be a rectangle. the hight is 3. and the diameter is 10

Step-by-step explanation:

The Correct Answer Is:  High-strength sports.

explanation:

Because for wrestling you have to use, you're strength. (And I just did the exam and I got it wrong for choosing the wrong answer, so I believe it's my answer. !!so, it's not high-power sports)

I hope it helps you!

:)

The distance between the coordinates A and B is 2 √(10) units.

A mathematical method called the distance formula is used to determine how far apart two points in a coordinate plane are from one another. It can be used with any two points (x1, y1) and (x2, y2) and is based on the Pythagorean theorem.

d = √((x2 - x1)² + (y2 - y1)²)

where d is the separation of the two spots.

To put it another way, we may visualise a right triangle created by the two locations and the horizontal and vertical lengths separating them to get the distance between them. The triangle's hypotenuse, or the distance between its two points, is measured using the distance formula.

The distance formula is given as:

d = √((x2 - x1)² + (y2 - y1)²)

Now, for the given coordinates we have:

d = √((1 - (-5))² + (3 - 1)²)

d = √(6² + 2²)

d = √(40)

d = 2 √(10)

Hence, the distance between A and B is 2 √(10) units.

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The probability of at least 10 cities out 45 have a commute time greater than 30 minutes is 0.893 or 89.3%

Apply the complement rule.

Probability that at least one of the 10 cities you select will have a commute time greater than 30 minutes,

The complement of the event is 'none of the 10 cities have a commute time greater than 30 minutes'.

The probability of the complement event can be calculated by ,

Multiplying probabilities of selecting a city with a commute time less than or equal to 30 minutes for each of 10 selections.

P(none of 10 cities have a commute time > 30 minutes) = (35/45) x (35/45) x ... x (35/45) (10 times)

Because there are 35 cities out of the total 45 that have a commute time less than or equal to 30 minutes.

So the probability that at least one of the 10 cities has a commute time greater than 30 minutes is,

1 - P(none of the 10 cities have a commute time greater than 30 minutes)

= 1 - (35/45) x (35/45) x ... x (35/45) (10 times)

= 1 - 0.1073

= 0.8926

Therefore, the probability that at least one of the 10 cities you select will have a commute time greater than 30 minutes is 0.893 or 89.3%.

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The above question is incomplete, the complete question is:

If i randomly sample two cities from this group (consider these 45 the 'population' if you will) then what is the probability that at least one of the 10 cities i select will have a commute time greater than 30 minutes?

the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.

How to solve the question?

To determine whether a triangle can be formed using the given side lengths, we need to apply the Triangle Inequality Theorem, which states that the sum of any two sides of a triangle must be greater than the third side.

Let's check each option:

A. XY = 11 mm, YZ = 12 mm, XZ = 18 mm

To form a triangle, we need to check whether the sum of any two sides is greater than the third side. Let's check:

XY + YZ = 11 mm + 12 mm = 23 mm > XZ = 18 mm

YZ + XZ = 12 mm + 18 mm = 30 mm > XY = 11 mm

XY + XZ = 11 mm + 18 mm = 29 mm > YZ = 12 mm

All the combinations are greater than the third side, so a triangle can be formed with these side lengths.

B. XY = 16 mm, YZ = 12 mm, XZ = 23 mm

Let's check whether the sum of any two sides is greater than the third side:

XY + YZ = 16 mm + 12 mm = 28 mm > XZ = 23 mm

YZ + XZ = 12 mm + 23 mm = 35 mm > XY = 16 mm

XY + XZ = 16 mm + 23 mm = 39 mm > YZ = 12 mm

Again, all the combinations are greater than the third side, so a triangle can be formed with these side lengths.

C. XY = 16 mm, YZ = 17 mm, XZ = 18 mm

Let's check whether the sum of any two sides is greater than the third side:

XY + YZ = 16 mm + 17 mm = 33 mm > XZ = 18 mm

YZ + XZ = 17 mm + 18 mm = 35 mm > XY = 16 mm

XY + XZ = 16 mm + 18 mm = 34 mm > YZ = 17 mm

All the combinations are greater than the third side, so a triangle can be formed with these side lengths.

D. XY = 11 mm, YZ = 12 mm, XZ = 28 mm

Let's check whether the sum of any two sides is greater than the third side:

XY + YZ = 11 mm + 12 mm = 23 mm < XZ = 28 mm

YZ + XZ = 12 mm + 28 mm = 40 mm > XY = 11 mm

XY + XZ = 11 mm + 28 mm = 39 mm > YZ = 12 mm

The first combination is less than the third side, so a triangle cannot be formed with these side lengths.

Therefore, the answer is (D) XY = 11 mm, YZ = 12 mm, XZ = 28 mm would NOT form a triangle with vertices X, Y, and Z.

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Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.

Inequality refers to the state of being unequal, uneven, or unfair in terms of social, economic, political, or other factors. It can be the result of various factors such as discrimination, prejudice, systemic biases, and unequal distribution of resources, opportunities, and power. Inequality can manifest itself in many forms, including income and wealth disparities, unequal access to education, healthcare, and housing, unequal treatment under the law, and marginalization of certain groups based on their race, gender, sexual orientation, religion, or other characteristics. Addressing inequality is an important challenge in creating a more just and equitable society.

to write an absolute value inequality with a solution set of 5 < x < 7, we need to use the form |x - b| < c, where b is the center of the solution set and c is the distance from the center to the edge of the solution set.

In this case, the center of the solution set is (5 + 7)/2 = 6, and the distance from the center to the edge is (7 - 5)/2 = 1.

Therefore, we can write the absolute value inequality as:

[tex]| x - 6 | < 1[/tex]

Alternatively, we can use the form |x - b| > c and write the absolute value inequality as:

[tex]x < 5 or x > 7[/tex]

Note that both of these absolute value inequalities have the same solution set as 5 < x < 7.

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Below is the answer to the questions:

Q 12.

The prediction is that there were about 260 principals in attendance at the conference.

Q13.

The best prediction is that the college will have about 480 students who prefer cookies.

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To find an expression for the width of the rectangle, we can use the formula for the area of a rectangle, which is:

Area = length x width

In this case, we know that the area is given by the expression +7x² + 11x + 2 and the length is given by the expression (x + 2). So we can substitute these values into the formula and solve for the width:

+7x² + 11x + 2 = (x + 2) x width

Expanding the right-hand side, we get:

+7x² + 11x + 2 = xwidth + 2width

Rearranging terms, we get:

+7x² + 11x + 2 - xwidth - 2width = 0

Factoring out the width, we get:

width*(x - 2) + 2*(x - 1) = 0

Dividing both sides by (x - 2), we get:

width = -2*(x - 1)/(x - 2)

Therefore, an expression for the width of the rectangle is:

width = -2*(x - 1)/(x - 2)

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