Check the picture below.
let's find the hypotenuse
[tex]\textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=\sqrt{a^2 + o^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{8}\\ o=\stackrel{opposite}{15}\\ \end{cases} \\\\\\ c=\sqrt{8^2+15^2}\implies \implies c=\sqrt{289}\implies c=17 ~\hfill \boxed{\sin( \theta )=\cfrac{\stackrel{opposite}{15}}{\underset{hypotenuse}{17}}}[/tex]
Andy has 3.2 x 10³ dollars in his bank account. His brother Dan has 4.7 times that amount in his account. How much does Dan have in his account? Write the amount in scientific notation.
Answer:
1.504 x 10^4
Step-by-step explanation:
SOMEONE HELP!!!!!!!!!!!!
Answer: It's none of these because the answer is 30.
How to perform bootstrapped likelihood ratio test?
To perform a bootstrapped likelihood ratio test, you need to fit the two nested models to your data, calculate the likelihood ratio test statistic, generate bootstrap samples, fit the two models to each bootstrap sample, calculate the p-value, and interpret the results.
The bootstrapped likelihood ratio test is a statistical method used to compare the goodness-of-fit of two nested models. Here's how you can perform a bootstrapped likelihood ratio test
Fit the two nested models: Start by fitting the two nested models to your data. One model is a restricted model, and the other is an unrestricted model that contains additional parameters.
Calculate the likelihood ratio test statistic: Calculate the likelihood ratio test statistic by subtracting the log-likelihood of the restricted model from the log-likelihood of the unrestricted model. This gives you the test statistic (often denoted as "LR").
Generate bootstrap samples: Generate a large number of bootstrap samples from the original dataset. Each bootstrap sample should be the same size as the original dataset and drawn with replacement.
Fit the two models to each bootstrap sample: For each bootstrap sample, fit the two nested models and calculate the likelihood ratio test statistic as described in steps 1 and 2.
Calculate the p-value: Calculate the p-value as the proportion of bootstrap samples for which the likelihood ratio test statistic is greater than or equal to the test statistic calculated from the original dataset.
Interpret the results: If the p-value is less than your chosen significance level (e.g., 0.05), you can reject the null hypothesis that the restricted model is better than the unrestricted model in favor of the alternative hypothesis that the unrestricted model is better.
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9. You just inherited land that was purchased in 1960 for $3,500. If the value of the land has increased 3%
each year until today, then what is the value of the land now?
9. The value of the land today, if the land was purchased for $3,500 in 1960, at the value increased at 3% per year is $22,532.7
What is a percentage increase?A percentage increase is the ratio of the difference in the initial and current value of an item to the initial value, expressed as a percentage.
The year the land was purchased = 1960
The amount at which the land was purchased, P = $3,500
The percentage rate by which the value of the land increased, r = 3%
The value of the land today, A, can be found using the compound interest formula as follows;
Value of the land, A = P·(1 + r)ⁿ
Where;
n = The number of years = 2023 - 1960 = 63
Therefore; A = 3500 × (1 + 3/100)⁶³ ≈ 22532.7
The value of the land today is about $22,532.7
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we randomly select 100 pell grant recipients from two states. state a is a relatively small state with approximately 4,000 pell grant recipients. state b is a large state with approximately 200,000 pell grant recipients. suppose that the mean and standard deviation in individual pell grants is approximately the same for both states: and . for which state is the sample mean for our 100 pell grant recipients most likely to be within $80 of $2,600?
The sample mean for 100 pell grant recipients is more likely to be within $80 of $2,600 for State A, given the relatively smaller population size and the use of the t-distribution.
To compare the two states, we need to calculate the probability of the sample mean for 100 pell grant recipients being within $80 of $2,600 for each state.
For State A, with only 4,000 pell grant recipients, the sample size of 100 is relatively large, but not enough to use the normal distribution. Therefore, we need to use the t-distribution, which has fatter tails than the normal distribution, making it more likely to produce extreme values. This means that the probability of the sample mean for 100 pell grant recipients being within $80 of $2,600 is higher for State A than for State B.
For State B, with a larger population of 200,000 pell grant recipients, the sample size of 100 is a small fraction of the population, allowing us to use the normal distribution. However, as the distribution is narrower than the t-distribution, the probability of the sample mean for 100 pell grant recipients being within $80 of $2,600 is lower for State B than for State A.
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PLEASE HELP ILL MARK U AS BRAINLIEST!!
Answer: 94 square inches 2
Step-by-step explanation:
2×(5×4 + 5×3 + 4×3) = 94 sq in 2
length x width x height
if you need more help with your ixl I am free to help!
have a good day!
What is the x intercept in the graph shown below?
-12
3
-3
4
help
Answer:
3
Step-by-step explanation:
The x-intercept is the place in a graph where the graph crosses the x-axis. After looking closely at the graph, we can see that it crosses the x axis at the point (4, 0), since 3 is the only whole number between 2 and 4.
Thus, the x-intercept is 3.
which of the following statements about the upper and lower control limits of a control chart is true? group of answer choices the upper control limit of an x-bar chart does not depend on the average range r-bar. the lower control limit of a p chart will always be a negative value. the upper and lower control limits for a p chart depend on the sample size. the upper and lower control limits of an r chart are always the same distance from r-bar.
The correct statement among the provided choices is: the upper and lower control limits for a p chart depend on the sample size.
A p-chart is used to monitor the proportion of defective items in a sample. The control limits depend on the sample size, as larger sample sizes typically result in smaller control limits. The other statements provided are not true.
The upper control limit of an x-bar chart does depend on the average range R-bar, the lower control limit of a p chart may not always be a negative value, and the upper and lower control limits of an R chart are not always the same distance from R-bar.
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Which number line represents the solution to the inequality
Answer:
B
Step-by-step explanation:
select the correct answer. in a box containing 20 cans, 12 of the cans contain vegetables. in the box, 5 of the cans are dented, with 2 of the dented cans containing vegetables. what is the probability that a randomly selected can in the box is dented or contains vegetables?
The probability that a randomly selected can in the box is dented or contains vegetables is 19/20.
To solve the problem, we need to use the formula for the probability of the union of two events:
P(A or B) = P(A) + P(B) - P(A and B)
where A and B are two events.
In this case, we want to find the probability that a randomly selected can is dented or contains vegetables. Let's call these events D and V, respectively.
We are given that there are 20 cans in total, 12 of which contain vegetables, and 5 of which are dented, with 2 of the dented cans containing vegetables. This information allows us to calculate the probabilities of the individual events
P(D) = 5/20 = 1/4
P(V) = 12/20 = 3/5
P(D and V) = 2/20 = 1/10
To find the probability of the union of these events, we plug these values into the formula
P(D or V) = P(D) + P(V) - P(D and V)
= 1/4 + 3/5 - 1/10
= 19/20
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011.considering grade c or above as a pass grade, how many students from this data successfully passed the course?
If we consider grade "C" or above as a pass grade, then the number of students who successfully passed the course are 10 students.
The Number of students who got grade "A" = 8,
The Number of students who got "B" grade is 2,
The Number of students who got grade "C" = 0,
The Number of students who got grade "D" = 0,
The Number of students who got grade "F" = 1,
Since the question asks for the number of students who successfully passed the course (i.e., grade "C" or above is considered a pass grade),
We add the number of students who got grades "A" and "B".
So, total number of students who successfully passed course are :
⇒ 8 (students who got grade "A") + 2 (students who got grade "B")
⇒ 10
Therefore, 10 students successfully passed the course.
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The given question is incomplete, the complete question is
If 8 students of the class got grade "A", 2 student got grade "B", No student got grade "C" and "D", 1 student got grade "F".
Considering grade "C" or above as a pass grade, how many students from this data successfully passed the course?
Dylan bought 3 identical shirts online for a total cost of $71.83 including a flat rate of $7.99 for shipping. Complete an equation to find the cost of each shirt, s, using the numbers below.
Answer:
$21.28
Step-by-step explanation:
We Know
Dylan bought 3 identical shirts online for a total cost of $71.83
$7.99 for shipping
We have the equation:
71.83 = 3s + 7.99
63.84 = 3s
s = $21.28
So, each shirt cost $21.28
#14 Please Help!!!!!!!!
The measure of the angle m∠FGH is 83°.
How to find the measure of m∠FGH?
Since the measure of an angle formed by a two tangents drawn from a point outside the circle is one-half the the difference of the intercepted arcs.
Thus, we can say:
m∠FGH = 1/2 * (∠FIH - 97°)
∠FIH = 360 - 97 = 263° (sum of angle in a circle)
m∠FGH = 1/2 * (263 - 97°)
m∠FGH = 1/2 * 166
m∠FGH = 83°
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A 150 pound crate is used to hold the boxes on the forklift. What is the maximum number of boxes that the forklift can carry in the crate.
Answer: To determine the maximum number of boxes that the forklift can carry in the crate, we need to know the weight of each box and the weight capacity of the forklift. Let's assume that each box weighs 20 pounds and the weight capacity of the forklift is 2000 pounds.
To find the maximum number of boxes, we need to subtract the weight of the crate from the weight capacity of the forklift and then divide by the weight of each box:
Maximum number of boxes = (Weight capacity of forklift - Weight of crate) / Weight of each box
Maximum number of boxes = (2000 - 150) / 20
Maximum number of boxes = 1850 / 20
Maximum number of boxes = 92.5
Since we cannot have a fraction of a box, we need to round down to the nearest whole number. Therefore, the forklift can carry a maximum of 92 boxes in the crate.
Step-by-step explanation:
the cylinder with the height of 4 M has a volume of 2,827.43 cubic meters find the length of the diameter
[tex]\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=2827.43\\ h=4 \end{cases}\implies 2827.43=\pi r^2(4)\implies \cfrac{2827.43}{4\pi }=r^2 \\\\\\ \sqrt{\cfrac{2827.43}{4\pi }}=r\hspace{5em}\stackrel{\textit{twice that is the \underline{diameter}}}{2\sqrt{\cfrac{2827.43}{4\pi }}} ~~ \approx ~~ \text{\LARGE 30}[/tex]
Mr. Frost worked 37 hours last week. He was paid $17 per hour. How much money did he make last week?
Answer:
$481
Step-by-step explanation:
37×$17=$481
he made $481
Solve by factoring Show all your steps
-x²-2x=0
xả +5x +1= 5x+2
x²-4x-8--6x
3x² +12=-21x-24
Solve by completing the square. Show all your steps.
x² - 4x = 32
x²-11 = -4x
Solve by using the Quadratic Formula. Show all your steps.
16x² +8x-8= 4
-x²-3x-13 = -2x²
Answer: To solve -x²-2x=0 by factoring, we can factor out x from the left-hand side:
x(-x-2) = 0
This equation is true if either x = 0 or -x-2 = 0. Solving for x in the second equation:
-x-2 = 0
-x = 2
x = -2
Therefore, the solutions to the equation -x²-2x=0 are x = 0 and x = -2.
To solve x²-4x-8--6x by factoring, we can simplify it first by combining like terms:
x²-10x-8 = 0
To factor this quadratic, we need to find two numbers that multiply to -8 and add to -10. These numbers are -2 and -8, so we can write:
x²-2x-8x-8 = 0
(x²-2x) - (8x+8) = 0
x(x-2) - 8(x+1) = 0
(x-8)(x-2) = 0
Therefore, the solutions to the equation x²-4x-8--6x are x = 8 and x = 2.
To solve 3x² +12=-21x-24 by completing the square, we first need to move all the terms to one side:
3x² + 21x + 36 = 0
Next, we divide both sides by 3 to simplify the coefficient of x²:
x² + 7x + 12 = 0
To complete the square, we need to add and subtract (7/2)² = 49/4 inside the parentheses:
x² + 7x + 49/4 - 49/4 + 12 = 0
(x + 7/2)² = 1/4
Taking the square root of both sides and solving for x, we get:
x + 7/2 = ±1/2
x = -7/2 ± 1/2
Therefore, the solutions to the equation 3x² +12=-21x-24 by completing the square are x = -4 and x = -3.
To solve -x²-3x-13 = -2x² by using the quadratic formula, we first need to move all the terms to one side:
-x² + x - 13 = 0
Next, we identify the coefficients a, b, and c:
a = -1, b = 1, c = -13
Substituting these values into the quadratic formula:
x = (-b ± sqrt(b² - 4ac)) / 2a
x = (-1 ± sqrt(1² - 4(-1)(-13))) / 2(-1)
x = (-1 ± sqrt(1 + 52)) / (-2)
x = (-1 ± sqrt(53)) / (-2)
Therefore, the solutions to the equation -x²-3x-13 = -2x² by using the quadratic formula are approximately x = -3.25 and x = 4.25.
Step-by-step explanation:
continued. what is the probability that at most 7 customers will arrive at the shop during a 5-minute interval?
The probability that at most 7 customers will arrive at the shop during a 5-minute interval is approximately 0.9485 or 94.85%.
To find the probability that at most 7 customers will arrive at the shop during a 5-minute interval, we need to sum the probabilities of 0, 1, 2, 3, 4, 5, 6, and 7 customers arriving.
Using the Poisson probability formula, the probability of k events occurring in a given interval is:
[tex]P(k) = (\lambda ^k \times e^(-\lambda)) / k![/tex]
where λ is the mean number of events in the interval.
In this case, λ = 4. Therefore, we have:
[tex]P(0) = (4^0 \times e^(-4)) / 0![/tex] ≈ 0.0183
[tex]P(1) = (4^1 \times e^(-4)) / 1![/tex]≈ 0.0733
[tex]P(2) = (4^2 \times e^(-4))[/tex]/ 2! ≈ 0.1465
[tex]P(3) = (4^3 \times e^(-4))[/tex] / 3! ≈ 0.1954
[tex]P(4) = (4^4 \times e^(-4))[/tex]/ 4! ≈ 0.1954
[tex]P(5) = (4^5 \times e^(-4))[/tex] / 5! ≈ 0.1563
[tex]P(6) = (4^6 \times e^(-4))[/tex] / 6! ≈ 0.1042
[tex]P(7) = (4^7 \times e^(-4))[/tex]/ 7! ≈ 0.0595
To find the probability that at most 7 customers will arrive, we add up these probabilities:
P(7) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7)
≈ 0.9485
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Find the length of each segment.
13. YW and WZ
The length of each segment is:
YW = 5 units
WZ = 8 units
How to find the length of each segment?The length of each segment can be found by using "bisector of an angle in a triangle theorem".
The theorem states that "the bisector of an angle in a triangle theorem divides the opposite sides in the ratio of the sides containing the angle".
Applying the theorem on the given triangle, we can say:
XY/XZ = YW/WZ
8/12.8 = (t/2)/(t-2)
8(t-2) = 12.8(t/2)
8t - 16 = 6.4t
8t - 6.4t = 16
1.6t = 16
t = 10
YW = t/2
YW = 10/2
YW = 5 units
WZ = t - 2
WZ = 10 - 2
WZ = 8 units
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an lti system has the frequency response function h(ω)=1/(jω 3). compute the output if the input is
The output of the LTI system with frequency response function [tex]h(w) = 1/(jw^3)[/tex], given an input[tex]x(t)[/tex], is:
[tex]y(t)[/tex]= inverse Fourier transform of [tex][1/(jw^3) X(w)][/tex]
To compute the output of an LTI system with frequency response function [tex]h(w) = 1/(jw^3)[/tex], given an input x(t), we can use the Fourier transform:
[tex]H(w)[/tex] = Fourier transform of [tex]h(t)[/tex]
[tex]X(w)[/tex] = Fourier transform of [tex]x(t)[/tex]
[tex]Y(w) = H(w) X(w)[/tex]
[tex]Y(w)[/tex] is the Fourier transform of the output [tex]y(t)[/tex].
Using the given frequency response function, we have:
[tex]H(w) = 1/(jw^3)[/tex]
Taking the Fourier transform of the input [tex]x(t)[/tex], we have:
[tex]X(w)[/tex] = Fourier transform of [tex]x(t)[/tex]
And multiplying [tex]H(w)[/tex] and[tex]X(w)[/tex], we get:
[tex]Y(w) = H(w) X(w) = 1/(jw^3) X(w)[/tex]
Taking the inverse Fourier transform of [tex]Y(w)[/tex], we get the output [tex]y(t)[/tex]:
[tex]y(t)[/tex] = inverse Fourier transform of [tex]Y(w)[/tex]
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A boat can travel at an average speed of 10 miles per hour in still water. Traveling with the current, it can travel 6 miles in the same amount of time it takes to travel 4 miles upstream.
Use the relationship [tex]t = \frac{d}{r}[/tex] to construct a rational equation that can be solved for x to find the speed of the current
The average speed of the current is 1 mile per hour.
To construct a rational equation that can be solved for the speed of the current, we can use the relationship t = d/r, where t is the time taken, d is the distance traveled, and r is the speed. We can set up two equations using this relationship, one for the upstream journey and one for the downstream journey:
Upstream journey: t = 4/(10-c)
Downstream journey: t = 6/(10+c)
Here, c represents the speed of the current. We use 10-c for the upstream journey because the current is going against the boat's direction, effectively reducing the boat's speed. Conversely, we use 10+c for the downstream journey because the current is aiding the boat's direction, effectively increasing the boat's speed.
Now, we can set these two equations equal to each other and solve for c:
4/(10-c) = 6/(10+c)
Multiplying both sides by (10-c)(10+c), we get:
4(10+c) = 6(10-c)
Simplifying and solving for c, we get:
c = 1
This means that when the boat is traveling with the current, its effective speed is 11 miles per hour, and when it's traveling upstream, its effective speed is 9 miles per hour.
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Evaluation researchers encounter more logistical problems than other researchers because evaluation researchA. occurs in the context of real life.B. takes longer.C. is more costly.D. has more measurement problems.E. examines more variables.
The answer is A. Evaluation researchers encounter more logistical problems than other researchers because evaluation research occurs in the context of real life.
Evaluation research often takes place in real-world settings, which can present logistical challenges such as accessing participants, coordinating schedules, and dealing with unexpected events. Additionally, evaluation research often involves multiple stakeholders and requires collaboration and communication among various groups, which can further complicate logistical issues. While evaluation research may also involve longer timelines, higher costs, measurement problems, and examination of multiple variables, these factors do not necessarily contribute to greater logistical challenges.
This means that evaluation researchers have to navigate complex, real-world situations, adapt to unforeseen challenges, and work with various stakeholders, making the research process more logistically challenging compared to controlled laboratory settings or theoretical research.
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Evaluation research is a type of research that focuses on assessing the effectiveness, efficiency, and impact of programs, policies, or interventions in real-life settings.
The correct answer is A. occurs in the context of real life.
This often involves evaluating the outcomes and impacts of interventions in complex and dynamic environments, such as organizations, communities, or systems. As a result, evaluation researchers may encounter more logistical problems compared to other types of researchers because they need to navigate real-life contexts, deal with multiple stakeholders, collect data from diverse sources, and address issues such as ethics, confidentiality, and validity in the evaluation process. Logistical problems may include challenges related to data collection, measurement, sample selection, data quality, and managing time and resources.
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you want to obtain a sample to estimate a population mean. based on previous evidence, you believe the population standard deviation is approximately . you would like to be 90% confident that your estimate is within 2.5 of the true population mean. how large of a sample size is required? n
The required sample size of the given estimate is 1090.9809
The population standard deviation is approximately σ = 50.2. You would like to be 90% confident that your estimate is within 1.5 of the true population mean.
What is Statistic?Statistics is the study of mathematics that deals with relations between comprehensive data.
Here,
For the 90% confidence the value of the z = 1.645
Now the sample size is given as,
n = [z × σ/2.5]²
Substitute values in the above equation,
n = [1.645×50.2/2.5]²
n = 1090.9809
Thus, the required sample size of the given estimate is 1090.9809.
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you are constructing a box from a piece of cardboard with dimensions 5 by 7 meters. you cut equal-size squares from each corner of the cardboard so you may fold the edges to construct the open top box. what are the dimensions of the box with the largest volume?
3.1634 m , w = 1.1634 , h = 1.91834 m are the dimensions of the box with the largest volume.
What is a simple volume definition?
Volume is defined as the space occupied within the bounds of an object in three-dimensional space. Also called the capacity of the object. The basic formula for the area of a rectangle is length x width, but the basic formula for volume is length x width x height.
Length of cardboard = 7 m
width of a cardboard = 5 m
let x be the side of square of piece cut from each corner
length of box = (7 -2x) m
width of box = (5 - 2x) m
height of box = x
volume V = (7 -2x) * (5 - 2x) * X
= (35 - 14X - 10X + 4X²) * X
= 4X³ - 24X² + 35X
If v is max v' = 0 and v'' < 0
v' = 12x² - 48x + 35
x = 6.0816 or 1.91834
if x = 6.0816 , box will not be follow.
x = 1.91834
v''(x) = 24x - 48
= 46.04 - 48 = -1.95 < 0
V is max.
length = 7 - 3.8366 = 3.1634 m
width = 5 - 3.8366 = 1.1634 m
height = 1.91834 m
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Tell whether a triangle can have the given angle measures. 115. 1∘, 47. 5∘, 93∘
No, a triangle cannot have the given angle measures, 115. 1∘, 47. 5∘, 93∘, as sum of these is greater than 180°.
The angle sum of a triangle will always be equal to 180°. The angle sum of a quadrilateral is equal to 360°, and a triangle can be created by slicing a quadrilateral in half from corner to corner. Since a triangle is essentially half of a quadrilateral, its angle measures should be half as well.
The sum of the angles in a triangle is always 180°, and 115.1° + 47.5° + 93° = 255.6°, which is greater than 180°.
Therefore, it is not possible for a triangle to have these angle measures.
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If line segment AC = 9 and Angle A = 34°, find line segment BC. Round to the nearest tenth.
Answer: BC ≈ 6.4 units
Step-by-step explanation: We can use trigonometry to find the length of line segment BC.
Since we know the length of AC and the measure of angle A, we can use the trigonometric function cosine (cos) to calculate BC.
Using the formula: cos(A) = Adjacent / Hypotenuse, we have
cos(34°) = BC / 9.
Solving for BC, we get BC ≈ 6.4 units (rounded to the nearest tenth).
Here is an article on trigonometry basics: https://byjus.com/maths/trigonometry/#:~:text=Trigonometry%20Basics,are%20based%20on%20these%20functions.
54 oranges cost 36 naira. Find the cost of 3 oranges
If 54 oranges cost 36 naira, then the cost of 3 oranges is 2 naira
Unitary method is a method of solving problems by finding the value of one unit and then using that value to find the value of a given number of units
To find the cost of 3 oranges, we can use unitary method which involves finding the cost of one orange and then multiplying it by 3.
Let's first find the cost of one orange
54 oranges cost 36 naira
So, 1 orange will cost:
1/54 of 36 naira = (36/54) naira = (2/3) naira
Now, we can find the cost of 3 oranges by multiplying the cost of one orange by 3
Cost of 3 oranges = 3 x (2/3) naira = 2 naira
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Round to the nearest 10th a cylinder is 22 inches and 12.5 inches what is the surface area 
solving systems by eliminations; finding the coeficients
please write all the problems down, 5 points for each problem, and Brainliest
The solution to the given system of equations is x = -3 and y = 4 or (-3,4)
How does the elimination approach work to solve an equation?Pick one of the variables (x or y) and remove it by adding or subtracting the equations in such a manner that one of the variables is cancelled out.Solve the resultant equation with only one variable for that variable.To solve for the other variable, plug the discovered variable value into one of the original equations.Now, for given problem
2x + 5y = 14 ................(1)
4x + 2y = -4 ................(2)
Multiply equation (1) by '2' and equation (2) by '-1' :
4x + 10y = 28 ................(3)
-4x - 2y = 4 ..................(4)
Adding equations (3) and (4) to eliminate 'x':
4x + 10y + (-4x) - 2y = 28 + (4)
8y = 32
y = 32 / 8
y = 4
on substituting the value (y = 4) into equation (1), we get :
2x + 5(4) = 14
2x + 20 = 14
2x = 14 - 20
2x = -6
x = (-3)
Hence, solution for the given system of equations is (-3,4).
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Point A = (5,4). If you rotated A 90 degrees about the point (2,-1), what would be the coordinates of A'?
Point A = (5,4). If you rotated A 90 degrees about the point (2,-1), the coordinates of A' is (-1,2).
Describe Rotation?Rotation is the process of rotating an object or a point around a fixed point or axis. In mathematics, rotation refers to a transformation that preserves the size and shape of an object while changing its orientation. It is a basic geometric transformation that is used in various fields, including mathematics, physics, engineering, and computer graphics.
In a two-dimensional space, a rotation is typically described by an angle of rotation and a fixed point, which is known as the center of rotation. The angle of rotation represents the amount by which the object is rotated, while the center of rotation is the point around which the object is rotated. In a three-dimensional space, a rotation is described by an axis of rotation and an angle of rotation.
To rotate point A 90 degrees counterclockwise about the point (2,-1), we can use the following formula:
A' = (x', y') = (a + (x - a) cosθ - (y - b) sinθ, b + (x - a) sinθ + (y - b) cosθ)
where (a,b) is the center of rotation and θ is the angle of rotation (90 degrees in this case).
Substituting the given values, we get:
a = 2, b = -1, x = 5, y = 4, θ = 90 degrees
x' = 2 + (5 - 2) cos(90) - (4 + 1) sin(90) = 2 - 3 = -1
y' = -1 + (5 - 2) sin(90) + (4 + 1) cos(90) = -1 + 3 = 2
Therefore, the coordinates of A' are (-1, 2).
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