Answers
Related Questions
The Molar Mass (g/mol) of an ideal gas whose density is 2.5g/L at 1.8 atm and 30,0 Celsius ?
35 g/mol
64 g/mol
44 g/mol
38 g/mol
Answers
Answer:
M = 35 g/mol
Explanation:
Given data:
Density = 2.5 g/L
Pressure = 1.8 atm
Temperature = 30°C (273.15 +30 = 303.15 K)
Molar mass = ?
Solution:
d = PM/RT
M = dRT/P
M = 2.5 g/L × 0.0821 atm.L/mol.K × 303.15 K / 1.8 atm
M = 62.22 atm. g/mol/ 1.8 atm
M = 35 g/mol
For a substance to change phases, the amount of internal energy must change. Water exists in three phases: liquid, solid (ice), and gas (water vapor) Which of the following lists the phases in order of increasing total energ/?
gas, liquid, solid
O solid, gas, liquid
o solid, liquid, gas
O liquid, gas, solid
Answers
Answer:
Solid, liquid, gas
Explanation:
add thermal energy to solid and it becomes liquid, add thermal energy to liquid it becomes gas
When 100.0 mL of 1.000 M HCl is reacted with 100.0 mL of 1.000 M NH4OH, the solution’s temperature increases 7.01 °C. Calculate LaTeX: \DeltaΔHreaction in units of kJ/mol. The specific heat of the salt solution is 4.184 J/g-°C and the density is 1.010 g/mL.
Do not use units or labels in answer. Make sure answer has the correct sig figs.
Answers
Answer:
Explanation:
volume of solution = 100 + 100 = 200 mL
mass of reaction mixture = 200 x 1.010 = 202 g
specific heat of solution mixture = 4.184 J/g-°C
heat evolved = mass x specific heat x rise in temperature
= 202 x 4.184 x 7.01
= 5924.63 J
100 mL of 1 M HCl
= .1 L of 1M HCl will contain .1 mole of HCl
.1 mole reacts with .1 mole of NH₄OH to make 5924.63 J of heat
1 mole reacts with 1 mole of NH₄OH to make 59246.3 J of heat
heat of reaction = 59246.3 J / mol
= 59.246 kJ / mol
= 59.3 kJ / mol .
i need help with this
Answers
Answer: B
Explanation: Most of the time they form over oceans which bring cool and moist weather.
What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?
Answers
Answer:
Ammonia is limiting reactant
Amount of oxygen left = 0.035 mol
Explanation:
Masa of ammonia = 2.00 g
Mass of oxygen = 4.00 g
Which is limiting reactant = ?
Balance chemical equation:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
Number of moles of ammonia:
Number of moles = mass/molar mass
Number of moles = 2.00 g/ 17 g/mol
Number of moles = 0.12 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 4.00 g/ 32 g/mol
Number of moles = 0.125 mol
Now we will compare the moles of ammonia and oxygen with water and nitrogen.
NH₃ : N₂
4 : 2
0.12 : 2/4×0.12 = 0.06
NH₃ : H₂O
4 : 6
0.12 : 6/4×0.12 = 0.18
O₂ : N₂
3 : 2
0.125 : 2/3×0.125 = 0.08
O₂ : H₂O
3 : 6
0.125 : 6/3×0.125 = 0.25
The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.
Amount of oxygen left:
NH₃ : O₂
4 : 3
0.12 : 3/4×0.12= 0.09
Amount of oxygen react = 0.09 mol
Amount of oxygen left = 0.125 - 0.09 = 0.035 mol
Suppose 215 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?
Answers
Answer:
The answer is "[tex]41.23 \ L\ N_2[/tex]"
Explanation:
[tex]2 NO_3^{-} + 10 e^{-} + 12 H^{+} \longrightarrow N_2 + 6 H_2O\\\\= \frac{( 215 \ g \ NO_3^{-})}{(62.0049 \frac{\ g NO_3^{-}}{mol})} \times \frac{(1 \ mol \ N_2}{ 2 \ mol \ NO_3^{-})}\\\\[/tex]
[tex]=3.46746789 \times 0.5\\\\= 1.733 \ mol \ N_2 \\\\\to V = \frac{nRT}{P} \\\\= (1.733 \ mol) \times (0.08205746 \frac{L\ atm}{Kmol}) \times \frac{ (17 + 273) K}{(1.00 atm)}\\\\= 41.23[/tex]
The volume of CO2 is 206.27 L
The ideal gas equation is used to determine the volume, pressure, temperature, or number of moles. It can be mathematically expressed as:
PV = nRT
From the given information:
The equation for the reaction can be expressed as:
[tex]\mathbf{2NO_3^-_{(aq)} + 5CO_{(g)} + 2H^+_{(aq)} \to N_2{(g)} + 5CO_2_{(g)} + H_2O_{(l)}}[/tex]
The mass of NO₃⁻ = 215 gThe temperature = 17.0°C = (273 + 17) = 290 KPressure = 1.00 atmThe number of moles of CO2 from the reaction is;
[tex]\mathbf{= \dfrac{215 \ g}{62.0049} \times \dfrac{5 \ mol \ of \ CO_2}{2 \ mol \ of \ NO_3^-} }[/tex]
[tex]\mathbf{= 8.669 \ moles \ of \ CO_2 }[/tex]
From ideal gas, by making the volume the subject of the, we have:
The volume of CO₂ [tex]\mathbf{V= \dfrac{nRT}{P}}[/tex]
[tex]\mathbf{V= \dfrac{8.669 \ moles \times 0.08205 L atm/ kmol \times 290\ K}{1 \ atm }}[/tex]
[tex]\mathbf{V= 206.27 \ L \ of \ CO_2 \ gas}[/tex]
Learn more about the volume of CO2 gas here 206.27 L
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In a car engine gasoline is burning to create mechanical energy which of the following statements is true? A. Some energy is lost as heat B. the total amount of energy in the system increases C. the total amount of energy in the system degrees D. the nuclear energy is transformed into mechanical energy
Answers
Answer:
Some energy is lost as heat
Explanation:
It is correct to say that as the gasoline is converted to mechanical energy in the automobile engine, some of the energy is lost as heat.
Heat energy is on of the ways energy is lost in any system. The movement of mechanical parts and even the combustion of the gasoline produces heat energy.
These energy are usually lost to the environment.
Name the following compounds
Answers
Answer:
What are the compounds
Explanation:
Answer:
Where is the picture?
Explanation:
how do the properties of alloys compare to the properties of the materials used to form them?
Answers
Answer:
An alloy is a mixture or metallic-solid solution composed of two or more elements. Examples of alloys include materials such as brass, pewter, phosphor bronze, amalgam, and steel. Complete solid solution alloys give single solid phase microstructure. Partial solutions give two or more phases that may or may not be homogeneous in distribution, depending on thermal history. An alloy’s properties are usually different from those of its component elements.
Examples of alloys include materials such as brass, pewter, phosphor bronze, amalgam, and steel. Complete solid solution alloys give single solid phase microstructure. Partial solutions give two or more phases that may or may not be homogeneous in distribution, depending on thermal history. An alloy’s properties are usually different from those of its component elements.
image
Steel: Steel is an alloy whose major component is iron.
Alloy constituents are usually measured by mass. An alloy is usually classified as either substitutional or interstitial, depending on its atomic arrangement. In a substitutional alloy, the atoms from each element can occupy the same sites as their counterpart. In interstitial alloys, the atoms do not occupy the same sites. Alloys can be further classified as homogeneous (consisting of a single phase), heterogeneous (consisting of two or more phases), or intermetallic (where there is no distinct boundary between phases).
Alloying a metal involves combining it with one or more other metals or non-metals, which often enhances its properties. For example, steel is stronger than iron, its primary element. Physical properties (density, reactivity, conductivity) of an alloy may not differ greatly from those of its constituent elements, but its engineering properties (tensile strength and shear strength) may be substantially different.
Explanation:
Roger has a car that accelerates at 5 m/s2. If the car has a mass 0f 1000 kg, how much force does the car produce?
Answers
Answer:
The answer is 5000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 1000 × 5
We have the final answer as
5000 NHope this helps you
Answer:
5OOON
Explanation:
IM SMARTTT
The average titration volume of the 0.09876 M NaOH used in back titration is 29.59
ml. Calculate the number of mmoles of HCl in the 250 ml volumetric flask.
Answers
Answer:
The number of moles of HCl in the 250 mL volumetric flask is 0.003 moles
Explanation:
Firstly, we solve for the concentration of acid using the formula
CaVa/CbVb = nₐ/nb
where Ca is the concentration of acid
Cb is the concentration of base
Va is the volume of acid
Vb is the volume of base
nₐ is the number of moles of acid (from the equation)
nb is the number of moles of base (from the equation)
Ca × 250/0.09876 × 29.59 = 1/1
Ca = 0.09876 × 29.59/250
Ca = 0.012 M
To determine the number of moles of HCl acid present in the 250 ml volumetric flask, the formula for molarity is used
Molarity = number of moles ÷ volume (in liter or dm³)
Volume needs to be converted to liter; 250 ml ⇒ 0.25 L
Molarity of the acid is 0.012 M
From the formula above, number of moles = molarity × volume (in liter)
number of moles = 0.012 × 0.25
number of moles of acid = 0.003 moles
Reactant A illustrates an example of which of the following?
Answers
Answer: molecules of an element
The diagram shown in the A section shows molecules of an element because they all look the same, and they are in circular shape.
- Best of Luck!
1. Which liquid sample is a pure substance?
Table 1: Boning point of the samples
Samples Temperature Observation while heating
Liquid A
Liquid B
2. Which soăc sample is a pure substance?
Scenario 1: Meiting point of the said samples
Samples Appearance Observation while melting
Solid
Solid B
Answers
The whole Activity , poem and paragraph is missing in the question.
Answer:
(1) Liquid A
(2) Solid A
Explanation:
Using this part of the given poem
Substances and mixtures behave differently,
During boiling and melting most especially
Boiling point of substance is fixed while mixture is not
Substance melts completely but mixture does not
The boiling point of the Pure substance remain fixed after reaching its boiling point this is shown by Liquid A
Solid A is melting completely so Solid A is a pure substance.
What are the oxidation states of the atoms in a diatomic gas?
Answers
it's d
o3o
(sorry still typing because I need 20 characters to submit this)
Electrons _______ around the nucleus of an atom.
Options:
- valence electrons
- atomic number
- atomic mass
- amu - atomic mass unit
- ionization energy
- electronegativity
- ionic bond
- covalent bond
- metallic bond
Answers
Answer:
Orbit/Orbital
Explanation:
Elections orbit around the nucleus of an atom.
A chemical compound has a molecular weight of 89.05 g/mole. 1.400 grams of this compound underwent complete combustion under constant pressure conditions in a special calorimeter. This calorimeter had a heat capacity of 2980 J °C.1 (Note that the calorimeter was made of a metal shell, a water "substitute" - a special oil, and a thermocouple). The temperature went up by 11.95 degrees.
Required:
Calculate the molar heat of combustion of the compound.
Answers
Answer:
[tex]\Delta _{comb}H=-2,265\frac{kJ}{mol}[/tex]
Explanation:
Hello!
In this case, for such calorimetry problem, we can notice that the combustion of the compound releases the heat which causes the increase of the temperature by 11.95 °C, it means that we can write:
[tex]Q _{comb}=-C_{calorimeter}\Delta T_{calorimeter}[/tex]
In such a way, we can compute the total released heat due to the combustion considering the calorimeter specific heat and the temperature raise:
[tex]Q _{comb}=-2980\frac{J}{\°C} *11.95\°C\\\\Q _{comb}=-35,611J[/tex]
Next, we compute the molar heat of combustion of the compound by dividing by the moles, considering 1.400 g were combusted:
[tex]n=1.400g*\frac{1mol}{89.05g} =0.01572mol[/tex]
Thus, we obtain:
[tex]\Delta _{comb}H=\frac{Q_{comb}}{n}=\frac{-35,611J}{0.01572mol} \\\\\Delta _{comb}H=-2,265,331\frac{J}{mol}*\frac{1kJ}{1000J} \\\\\Delta _{comb}H=-2,265\frac{kJ}{mol}[/tex]
Best regards!
The ratio of effusion ratios between He(g) and SF6(g) is
Answers
rate He = 6 x rate SF₆
Further explanationGraham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
[tex]\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }[/tex]
or
[tex]\rm M_1\times r_1^2=M_2\times r_2^2[/tex]
M He = 4 g/mol
M SF₆ = 146 g/mol
[tex]\tt \dfrac{r_{He}}{r_{SF_6}}=\sqrt{\dfrac{146}{4} }=6.04\approx 6\\\\r_{He}=6~r_{SF_6}[/tex]
equation for the oxidation of octane.
Answers
Answer:
I think its 2 C8H18 + 25 O2 = 18 H2O + 16 CO2
Im not sure!
Explanation:
Fove seconds without gravity would be detrimental to earth.
A.True
B.False
Answers
Answer:true
Explanation:
Which energy transformation takes place in a generator?
Question 2 options:
A. mechanical to electrical
B. chemical to radiant
C. electrical to mechanical
D. radiant to electrical
Answers
In order for photosynthesis to take place
what must be present?
Answers
Answer:
For photosynthesis to take place, plants need to take in carbon dioxide (from the air), water (from the ground) and light (usually from the sun)
Explanation:
Answer:
water carbon dioxide sunlight and the plant
Explanation:
why sulphur dichloride has higher boiling point than sulphur hexafluoride?
Answers
Explanation:
Sulphur dichloride has higher boiling point as compare to sulphur hexafluoride because
Sulphur dichloride has stronger intermolecular forces among the molecules and sulphur hexafluoride has weaker intermolecular forces among molecules.
Stronger the intermolecular forces higher the boiling point that the reason sulphur dichloride has a higher boiling point than the sulphur hexafluoride.
Help Plz 20 points -------------
Answers
Answer:
B
Explanation:
Compounds are made up of 2 or more different atoms that bond to form a compound.
:))))
The density of a metal is 11.4 g/cm3. How much volume (in cm3) would a sample of 30.5 g have?
Answers
The Concept:
We are given the density of a sample of the metal = 11.4 grams / cm³
and we need to find the volume occupied by a sample of 30.5 grams
For this solution, we will use dimensional analysis
from the given information, we can also say that the density of the metal is:
1 cm³ / 11.4 grams
If we multiply this value by 30.5 grams, the 'grams' in the numerator and the denominator will cancel out and we will be left with the volume occupied by 30.5 grams of the metal
Solving for the volume:
[tex]\frac{ 1 cm^{3} }{11.4 grams}[/tex] X 30.5 grams = (30.5 / 11.4) cm³
Volume of 30.5 grams of the sample = 2.68 cm³
A sample of 18.0 g of O2 has a temperature of 350 K, and pressure of 0.720 atm. What is the volume of the sample?
Answers
Answer:
V = 22.36 L
Explanation:
Given data:
Mass of oxygen = 18.0 g
Temperature = 350 K
Pressure = 0.720 atm
Volume of gas = ?
Solution:
Number of moles of oxygen :
Number of moles = mass/molar mass
Number of moles = 18.0 g/ 32 g/mol
Number of moles = 0.56 mol
Volume of oxygen:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
0.720 atm × V = 0.56 mol × 0.0821 atm.L/ mol.K × 350 K
V = 16.1 atm.L /0.720 atm
V = 22.36 L
You start with 4800 grams uranium - 238. It's radioactive and goes
through alpha decay. How many grams remain after 7 half-lives.
Answers
Answer:
37.5g
Explanation:
The half-life is the time taken for a radioactive substance to decay to half its original composition;
Original composition here is = 4800g of U-238
How many grams remain after 7 half-lives;
After each life, the uranium reduces by half;
Amount remaining = 4800 x [tex](\frac{1}{2})^7[/tex]
= 37.5g
After 7 half lives, 37.5g of the original sample will remain.
what is an advantage of power plants powered by natural gas when compared to coal and oil
Answers
What process that occurred in the Midwestern United States in the 1930s is now occurring in the Sahel region of Africa, south of the Sahara Desert?
Industrial pollution
Radioactive soil
Over fertilization of streams
Dust storms and desertification
Answers
Answer:
dust storms and desertification
Explanation:
Answer:
Dust storms and desertification
Explanation:
1) Describe the appearance of each of the three curves on your graph.
Answers
Answer:PROCESSING THE DATA To analyze the relationship between conductivity and volume, use this method to calculate the linear-regression statistics for your data. Then plot the linear regression curve on your graph. Note the conductivity of pure water: 0 uS/cm Conductivity Data Table Drops 1M NaCl(aq) 1M CaCl2(ag) (uS/cm) (uS/cm) 1 150 uS/cm 110 uS/cm 2 280 uS/cm 155 uS/cm 405 uS/cm 245 uS/cm 4 516 uS/cm 340 uS/cm 3 Use 1 mL = 20 drops to Plot Conductivity (in the y axis) vs. volume of each salt solution (x axis). Do a best fit straight line through these points. Make sure to use the pure water conductivity as your zero drop. On this same graph determine the slope for both the NaCl and CaCl2, make sure to use pure water as your 0 drop. Sketch your prediction of what you would expect the AlCl3 drops to look like.
Explanation:
Give reasons.
a.Steel is an alloy.
b.Sodium is a metal.
Answers
Answer:
steel is an alloy because steel when other elements comprising metals and nonmetals are added to Carbon steel , alloy steel is formed.Sodium is a metal because it is highly reactive metal.it is the member of alkali metal family about the periodic table .it has one electron in the outermost electron shell.Explanation:
Hope it's help !