V2=u2+2as v 2 = u 2 + 2 a s Where v v is the final velocity (in m/s), u u is the initial velocity (in m/s), a a is the acceleration (in m/s²) and s s is the distance (in meters). Find v v when u u is 9 m/s, a a is 7 m/s², and s s is 28 meters.

Answers

Answer 1

Answer:

Final velocity, v = 21.75 m/s

Step-by-step explanation:

Given that the relation between final velocity, initial velocity, acceleration and distance traveled is expressed as:

[tex]v^2=u^2+2as[/tex]

Also, given that:

Initial velocity, u = 9 m/s

Acceleration, a = 7 m/[tex]s^2[/tex]

Distance, s = 28 m

To find:

Final velocity, v = ?

Solution:

The given relation between v, u, a and s is:

[tex]v^2=u^2+2as[/tex]

We have the values of initial velocity, acceleration and distance traveled in the question statement. We just need to put all these values to find the value of final velocity.

Let us put all the values in the given equation and try to find final velocity, v:

[tex]v^2=9^2+2\times 7 \times 28\\\Rightarrow v^2=81+14 \times 28\\\Rightarrow v^2=81+392\\\Rightarrow v^2=473\\\Rightarrow v=\sqrt{473}\\\Rightarrow v=21.75\ m/s[/tex]

So, the answer is:

final velocity, v = 21.75 m/s


Related Questions

In a different plan for area codes the first digit could be any number from 3 through 6 the second digit was either 5,6,7 or 8 and the third digit could be any number except 5. With this plan how many different area codes are possible?

Answers

Answer:

144 codes are possible

Step-by-step explanation:

Okay for the first digit, we shall be selecting one out of 3,4,5,6.

Meaning we are selecting one out of four choices

The number of ways this can be done is 4C1 ways = 4 ways

For the second digit, we have 5,6,7 or 8, we are still selecting 1 out of 4 selections and the number of ways we can do this is also 4 ways

And lastly , we can choose any digit for the last number expect 5 , so from 0 to 9, we are removing 1 which means we are left with 9 choices

So the number of different area codes possible are ; 9 * 4 * 4 = 144 codes

If a number is added to the numerator of StartFraction 11 Over 36 EndFraction and twice the number is added to the denominator of StartFraction 11 Over 36 EndFraction ​, the resulting fraction is equivalent to one third . Find the number.

Answers

Answer:

The number is 3

Step-by-step explanation:

The fraction is 11/36

let

x = no. added to the numerator

2x = no. added to denominator

We have,

x+11/2x+36=1/3

Cross multiply

3(x+11) = (2x + 36)

3x + 33 = 2x + 36

Collect like terms

3x - 2x = 36 - 33

x=3

The number is 3

Check:

3+11/6+36=1/3

14/42=1/3

which geometric solid is formed by rotating the rectangle about line m?

Answers

Answer:

rectangular prism

Step-by-step explanation:

check by rotating the shape in images

Emily put $3000.00 in a 2 year CD paying 4% interest compounded monthly. After 2 years she withdrew all her money. What is the amount of the withdrawl?

Answers

Answer:

A=3244.8 dollars

Step-by-step explanation:

A=p(1+r)^t

A=3000(1+0.04)^2

A=3244.8 dollars

PLS HELP !! I’ll appreciate it

In a two-column proof, what would you write in the reason column for any statement that is given to
you?

Answers

Answer:

explanation

Step-by-step explanation:

the reason for your statement is just your explanation of why you think that.

Please help me.. I'm very confused about this

Answers

Answer:

C

Step-by-step explanation:

1:draw a very simple Cartesian plane for the graph

2:label the quadrants 1-4 from top right round to bottom right as 4

3:then apply x>0 (1,2) is top right and y<0 is bottom right (-1,-2)

3m-(m + 5) when m = 11 help

Answers

Answer:

17

Step-by-step explanation:

3m-(m + 5)

Distribute the minus sign

3m -m -5

Combine like terms

2m -5

Let m =11

2*11 -5

22-5

17

Answer:

[tex]17[/tex]

Step-by-step explanation:

[tex]3m-(m + 5)[/tex]

[tex]m= 11[/tex]

Plug m as 11 in the expression.

[tex]3(11)-(11+5)[/tex]

Evaluate.

[tex]33-16[/tex]

[tex]=17[/tex]

The variables m and n are inversely correlated. When m = 22, n = 51. What is m when n = 6?

Answers

Answer:

m = 187

Step-by-step explanation:

Given m and n are inversely correlated then the equation relating them is

m = [tex]\frac{k}{n}[/tex] ← k is a constant

To find k use the condition when m = 22, n = 51

22 = [tex]\frac{k}{51}[/tex] ( multiply both sides by 51 )

1122 = k

m = [tex]\frac{1122}{n}[/tex] ← equation of correlation

When n = 6, then

m = [tex]\frac{1122}{6}[/tex] = 187

The value of m will be equal to 187 when both the numbers are an inverse function of each other.

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that m and n are inversely correlated then the equation relating them is

m = K / n ← k is a constant

To find k use the condition when m = 22, n = 51

22 = k / 51 ( multiply both sides by 51 )

1122 = k

m =  1122 / n ← equation of correlation

When n = 6, then

m = 1122 / 6  = 187

Therefore, the value of m will be equal to 187 when both the numbers are an inverse function of each other.

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My age if I am half as old as two more than twice Mack's age if Mack is m years old.

Answers

Answer:

You are m + 1 years old.

Step-by-step explanation:

Let's say that you are x years old, and Mack is m years old.

x = 1/2( two plus twice m)

x = 1/2(2 + 2m)

x = 1 + m

x = m + 1

Hope this helps!

Human is correct , good job human c:

If you bisect an angle that is 128 degrees, what size are the two new angles?

Answers

Answer:

64 is the answer

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stay at home stay safe

Answer:

Each angles measures 64 degrees

Step-by-step explanation:

Bisect means divide in half

128/2 = 64

Each angles measures 64 degrees

There are four inequalities that define the region R.
One of these is y Find the other three inequalities,

Answers

Answer:

[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]

Step-by-step explanation:

The region R is surrounded by 4 lines, the first one is y=x+1, the second one is y=0 or the axis x, and the third and fourth one need to be calcualted.

To find the equation of a line through the points (x1,y1) and (x2, y2) we can use the following equation:

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Then, our third line is going to be the line that passes through the points (2,0) and (4,3), so the equation is:

[tex]y=\frac{3-0}{4-2}(x-2)\\y=\frac{3}{2}x-3[/tex]

Our fourth line is the line that passes through the points (3,0) and (0,3), so the equation is:

[tex]y=\frac{3-0}{0-3}(x-3)\\y=-x+3[/tex]

Then we can say that the other three inequalities are:

[tex]y\geq 0\\y\geq \frac{3}{2}x-3\\ y\leq -x+3[/tex]

|3x+9|= 30

Answer: x=7, -13

Answers

Answer:

[tex]\boxed{x=7, \: x=-13}[/tex]

Step-by-step explanation:

[tex]|3x+9|= 30[/tex]

Solve for absolute value.

There are two possibilities.

One possibility:

[tex]3x+9=30\\3x=21\\x=7[/tex]

Second possibility:

[tex]3x+9=-30\\3x=-39\\x=-13[/tex]

You need to find the volume of the plastic sphere that holds the gum in your gumball machine. If the diameter is 2 feet, what is the volume? Use 3.14 to approximate pi. Round your answer to the nearest hundredth.

Answers

Answer:

The volume is

4ft³

Step-by-step explanation:

Volume of a sphere is given by

[tex]V = \frac{4}{3} \pi {r}^{ 3} [/tex]

where r is the radius

π = 3.14

From the question we were given the diameter and

radius = diameter/ 2

diameter = 2 feet

radius = 2/2 = 1 feet

So the volume of the sphere is

[tex]V = \frac{4}{3} (3.14)(1) ^{3} [/tex]

[tex] = \frac{4}{3} \times 3.14[/tex]

V = 4.186

We have the final answer as

V = 4 ft³ to the nearest hundredth

Hope this helps you

solve for x ax+3x=bx+5

Answers

Answer:

x=5/a-b+3

Step-by-step explanation: Since we don't know a or b, we'll leave them as is. Shift all terms with x to the left and keep 5 on the right (ax+3x-bx)=5. x is a factor of that, so you'd change it to x(a-b+3)=5. Then, divide by (a-b+3). If a and b had set values, then just add all the x values and solve.

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Lets do this step by step.

Simplify 5 by ( b - x)

Apply the distributive property.

[tex]5b + 5 ( -x ) = 2b + ax[/tex]

Multiply -1 by 5.

[tex]5b - 5x = 2b + ax[/tex]

Subtract ax from both sides of the equation.

[tex]5b - 5x - ax = 2b[/tex]

Move all terms not containing x  to the right side of the equation.

Subtract 5b from both sides of the equation.

[tex]-5x - ax = -3b[/tex]

Subtract 5b from 3b.

[tex]-5x - ax = -3b[/tex]

Factor x out of -5x - ax .

[tex]x ( -5 - a ) = -3b[/tex]

Divide each term by = -3b.

Divide each term in x ( -5 - a) = -3b by - 5 -a.

[tex]\frac{x( -5 - a)}{-5 - a} = \frac{-3b}{-5 - a}[/tex]

Cancel the common factor of -5 - a.

[tex]x = \frac{-3b}{-5 - a}[/tex]

Simplify [tex]\frac{-3b}{-5 - a}[/tex]

[tex]x = \frac{3b}{5 + a}[/tex]

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If the family decreases the clothing budget by 3 percent, what amount will it have to spend on clothing?

nearest dollar

$266

$466

$645

$665

Answers

Answer: $466

Step-by-step explanation:

Answer:

b.$466

Step-by-step explanation:

What is the total number of common tangents that can be drawn to the circles?

Answers

Answer:

The answer would be zero. This is due to the fact that the tangent is a line on a point around the circle. These two circles share no common tangents.

Step-by-step explanation:

The number of the common tangent to the concentric circles is zero. Option D is correct.

Two concentric circles are given in the figure, and common tangents to the circles are to be determined.

What is a circle?

The circle is the locus of a point whose distance from a fixed point is constant i.e center ( h, k ). The equation of the circle is given by[tex](x-h)^2 + (y-k)^ = r^2[/tex]. where h, k is the coordinate of the center of the circle on the coordinate plane and r is the radius of the circle.

Since the line passes through the circumference of the circle is known as a tangent to the circle and the common tangent of the concentric circle is not possible because the tangent to the inner circle results secant to the outer circle.

Thus, the number of the common tangent to the circles is zero. Option D is correct.

Learn more about circle here:

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What is the result of adding these two equations?
62 + 2y = -2
3x - 2y = -5

Answers

Answer:

x = -7/9; y = 4/3.

Step-by-step explanation:

I will assume that the top equation is 6x + 2y = -2, and the bottom one is 3x - 2y = -5.

If you add the two...

(6x + 3x) + (2y + (-2y)) = (-2 + (-5))

9x + 0 = -7

9x = -7

x = -7/9

6(-7/9) + 2y = -2

-42/9 + 2y = -18/9

2y = 24/9

y = 24/18

y = 12/9

y = 4/3

Hope this helps!

DatGuy! Sekkrit! Wishing! Anyone? Find the discriminant of 3x²+5x-2 = 0

Answers

Answer:

49

Step-by-step explanation:

[tex]3x^2+5x-2 = 0[/tex]

Apply discriminant formula : [tex]D = b^2- 4ac[/tex]

[tex]D=discriminant\\b=5\\a=3\\c=-2[/tex]

[tex]D = b^2- 4ac[/tex]

Plug in the values for a, b, and c.

[tex]D = 5^2- 4(3)(-2)[/tex]

Evaluate.

[tex]D = 25- 12(-2)[/tex]

[tex]D = 25- - 24[/tex]

[tex]D=25+24[/tex]

[tex]D=49[/tex]

Answer:

49

Step-by-step explanation:

3x²+5x-2 = 0

This is in the form

ax^2 + bx + c=0

a=3  b=5  c = -2

The discriminant is

b^2 -4ac

5^2 -4(3) (-2)

25 + 24

49

The discriminant is 49

an orphanage bought 119 1/4 m of cloth to stitch dresses for kids. The dress for one kid requires 2 1/4m of cloth. How many dresses of the size can be stitched

Answers

Answer:53 dresses

Step-by-step explanation:

First of all..if one kid required 2 1/4m of cloth,what about 119 1/4m of cloth?

So u take 119 1/4m of cloth and divide it by 2 1/4m of cloth.

Then change the mixed numbers into improper fractions.

So the question will be 477/4 m divided by 9/4 m.

The second improper fraction (9/4)m will be reciprocated to be (4/9)m.

Afterwards,take 477/4 m and multiply it by 4/9 m.

The result will be 53 dresses.

Solve this problem. Reduce to lowest terms.
John worked in his garden for 4 3/4hours on Saturday and 2 1/2 hours on Sunday. How
many hours did he work in all?
6 hours
O 74 hours
4 hours
5 hours

Answers

Answer:

7 1/4

Step-by-step explanation:

4 3/4 + 2 1/2 =

4 3/4 +2 2/4 =7 1/4

Answer:

7 1/4 hours

Step-by-step explanation:

4 3/4 + 2 1/2

Get a common denominator

4 3/4 + 2 2/4

6 5/4

Rewriting as

6 + 4/4 + 1/4

6 + 1 + 1/4

7 1/4 hours

find three examples of corporate logos. do they incorporate symmetry? if so, and what kind? your response should be 3-5 sentences long

Answers

Answer:

Symmetry is the property of an object to retain its shape even if it is turned or turned.

The three corporate logos are McDonald, Shell, Snapcaht

McDonald company logo is symmetrical and it is a reflective symmetry.

Shell logo is symmetrical and it is also reflective symmetry.

Snaphcat logo is symmetrical and it is also reflective symmetry.

1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.

2. compare the following ratios

i) 2:3 and 4:5
ii) 11:19 and 19:21
iii) ½ : ⅓ and ⅓ : ¼
iv ) 1⅕ : 1⅓ and ⅖ : 3/2

v) if a : b = 6:5 and b:c = 10:9, find a:c

vi) if x : y = ⅙:⅛ and y : z = ⅛: ⅒, find X : z

sorry many questions​

Answers

Answer:

Step-by-step explanation:

Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.

If the weight of an alloy = x kgs

Then weight of copper = [tex]\frac{9}{7+9}\times (x)[/tex]

                                      = [tex]\frac{9}{16}\times (x)[/tex]

And the weight of zinc = [tex]\frac{7}{7+9}\times (x)[/tex]

                                      = [tex]\frac{7}{16}\times (x)[/tex]

If the weight of zinc = 31.5 kg

31.5 = [tex]\frac{7}{16}\times (x)[/tex]

x = [tex]\frac{16\times 31.5}{7}[/tex]

x = 72 kgs

Therefore, weight of copper = [tex]\frac{9}{16}\times (72)[/tex]

                                               = 40.5 kgs

2). i). 2 : 3 = [tex]\frac{2}{3}[/tex]

        4 : 5 = [tex]\frac{4}{5}[/tex]

Now we will equalize the denominators of each fraction to compare the ratios.

[tex]\frac{2}{3}\times \frac{5}{5}[/tex] = [tex]\frac{10}{15}[/tex]

[tex]\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}[/tex]

Since, [tex]\frac{12}{15}>\frac{10}{15}[/tex]

Therefore, 4 : 5 > 2 : 3

ii). 11 : 19 = [tex]\frac{11}{19}[/tex]

    19 : 21 = [tex]\frac{19}{21}[/tex]

By equalizing denominators of the given fractions,

[tex]\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}[/tex]

And [tex]\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}[/tex]

Since, [tex]\frac{361}{399}>\frac{231}{399}[/tex]

Therefore, 19 : 21 > 11 : 19

iii). [tex]\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}[/tex]

             [tex]=\frac{3}{2}[/tex]

     [tex]\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}[/tex]

              = [tex]\frac{4}{3}[/tex]

Now we equalize the denominators of the fractions,

[tex]\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}[/tex]

And [tex]\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}[/tex]

Since [tex]\frac{9}{6}>\frac{8}{6}[/tex]

Therefore, [tex]\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}[/tex] will be the answer.

IV). [tex]1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}[/tex]

                  [tex]=\frac{6}{5}\times \frac{3}{4}[/tex]

                  [tex]=\frac{18}{20}[/tex]

                  [tex]=\frac{9}{10}[/tex]

Similarly, [tex]\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}[/tex]

                       [tex]=\frac{4}{15}[/tex]                  

By equalizing the denominators,

[tex]\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}[/tex]

Similarly, [tex]\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}[/tex]

Since [tex]\frac{270}{300}>\frac{80}{300}[/tex]

Therefore, [tex]1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}[/tex]

V). If a : b = 6 : 5

     [tex]\frac{a}{b}=\frac{6}{5}[/tex]

        [tex]=\frac{6}{5}\times \frac{2}{2}[/tex]

        [tex]=\frac{12}{10}[/tex]

  And b : c = 10 : 9

  [tex]\frac{b}{c}=\frac{10}{9}[/tex]

 Since a : b = 12 : 10

 And b : c = 10 : 9

 Since b = 10 is common in both the ratios,

 Therefore, combined form of the ratios will be,

 a : b : c = 12 : 10 : 9

One liter of paint is needed to cover all 6 sides of a cubical block. How many liters will be needed to cover all 6 sides of a second cubical block whose edge is twice as long as an edge on the first block?

Will mark brainlist

Answers

Answer:

4 liters

Step-by-step explanation:

Let's assume that the side lengths of the cubical block are 2 inches.

This means that one of the sides area is 4 in².

Multiplying this by 6 (for there are 6 sides) gets us 24 in².

So one liter of paint covers 24 in².

Now if the side lengths (edge) of the second block is doubled, that means that the side lengths are [tex]2\cdot2 = 4[/tex] inches.

So the area of one side is 16 in².

Multiplying this by 6 (as there are 6 sides) gets us 96 in².

To find how many liters of paint this will take, we divide 96 by 24.

[tex]96\div24=4[/tex]

So 4 liters of paint will be needed for the second cubical block.

Hope this helped!

Find the fraction half way between 1/7 and 1/5

Answers

Answer:

6/35

Step-by-step explanation:

add ¹/7+¹/5 =12/35

divide 12/35 by 2

=6/35

Please answer this in two minutes

Answers

Answer:

366.6 mm²

Step-by-step explanation:

Step 1: find XY using the Law of sines.

Thus,

[tex] \frac{XY}{sin(W)} = \frac{WY}{sin(X)} [/tex]

m < W = 180 - (70+43) (sum of angles in a triangle)

W = 180 - 113 = 67°

WY = 24 mm

X = 43°

XY = ?

[tex] \frac{XY}{sin(67)} = \frac{24}{sin(43)} [/tex]

Cross multiply:

[tex] XY*sin(43) = 24*sin(67) [/tex]

[tex] XY*0.68 = 24*0.92 [/tex]

Divide both sides by 0.68 to solve for XY

[tex] \frac{XY*0.68}{0.68} = \frac{24*0.92}{0.68} [/tex]

[tex] XY = 32.47 [/tex]

XY ≈ 32.5 mm

Step 2: find the area using the formula, ½*XY*WY*sin(Y).

Area = ½*32.5*24*sin(70)

Area = ½*32.5*24*0.94

= 32.5*12*0.94

Area = 366.6 mm² (nearest tenth)

HELPPPP,Which of the following choices is the length of AB if A (-3, -2) and B (5, -4)? AB = 2 AB = 68 AB = 4 None of these choices are correct

Answers

Answer: [tex]\sqrt{68}[/tex] units is the exact length of AB

===============================================

Explanation:

Use the distance formula to get this answer. The idea is you subtract the x coordinates together, and do the same for the y coordinates as well. Square each result and add up those squares. The last step of the formula is to apply the square root to get the distance from A to B, which is also the length of segment AB.

[tex]d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(-3-5)^2+(-2-(-4))^2}\\\\d = \sqrt{(-3-5)^2+(-2+4)^2}\\\\d = \sqrt{(-8)^2+(2)^2}\\\\d = \sqrt{64+4}\\\\d = \sqrt{68}\\\\[/tex]

Therefore, [tex]AB = \sqrt{68}[/tex]

Explain please --

Find the measure of angle A to the nearest degree.

a. 26
b. 27
c. 63

Answers

Answer: C.  63 degrees

Explanation:

We'll use the tangent ratio to connect the opposite and adjacent sides with the reference angle

tan(angle) = opposite/adjacent

tan(A) = 14/7

Then use the arctangent function (aka inverse tangent) to fully isolate A

A = arctan(14/7)

A = 63.4349 degrees approximately; make sure your calculator is in degree mode

Round this to the nearest whole number to get 63.

anyone plss heeelp me...​i only need answer 6c..

Answers

Answer:

6c1;   [tex]Area = 81.12m^2[/tex]

6cii:  See Explanation

Step-by-step explanation:

Given

[tex]A = 3p^2[/tex]

[tex]0 \leq p \leq 6[/tex]

Where A represents Area and P represents Width

Required

Solve 6c

Please note that because you only need 6c, I'll solve using calculations;

Solving 6ci:

Area of the cage, when width is 5.2m

Substitute 5.2m for p in[tex]A = 3p^2[/tex]

[tex]A = 3 * 5.2m^2[/tex]

[tex]A = 3 * 27.04m^2[/tex]

[tex]A = 81.12m^2[/tex]

Hence, the area of the cage is 81.12m²

Solving 6cii:

Area of the cage, when width is 40m

From the range of value of p:   [tex]0 \leq p \leq 6[/tex], 40m is out of range of the values of p

However, if the range is extended; the value of Area is as follows;

Substitute 40m for p

[tex]A = 3 * 40m^2[/tex]

[tex]A = 3 * 1600m^2[/tex]

[tex]A = 4,800m^2[/tex]

The cosine function reaches a value of 0 when x is equal to

Answers

Answer:

Step-by-step explanation:

The values ​​of the cosine function are represented by the axis OX of the goniometric circumference (circumference centered at the origin and of radius 1). Therefore the cosine is zero for the 90º and 270º angles.

02.06A LC) Which number is not in scientific notation? 02.06A

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the answer is (A) you cant have 11 it should be 1.1 x 10^22

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