Answer:
Side e = 5.7
Step-by-step explanation:
Given
d = 10
f = 7
<E = 34°
Required
Calculate length of side e
This can be calculated using law of cosine as follows;
e² = d² + f² - 2 * d * f * Cos(<E)
Substitute 10 for d, 7 for f and 34 for <E. This gives
e² = 10² + 7² - 2 * 10 * 7 * cos34
e² = 100 + 49 - 140 * cos34
e² = 100 + 49 - 140 * 0.8290
e² = 100 + 49 - 116.06
e² = 32.94
Take Square Root of both sides
e = √32.94
e = 5.7 (Approximated)
PLEASE HELP BRAINLY - which option is correct?
Answer:
[tex]y > \frac{2x}{3} + 1[/tex]
Step-by-step explanation:
Given:
The graph in the attachment where the coordinates are (3,3) and (-3,-1)
Required:
Which inequality represent the graph
The first step is to determine the slope of the graph
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Where m represents the slope, [tex](x_1, y_1) = (3,3)[/tex] and [tex](x_2, y_2) = (-3,-1)[/tex]
[tex]m = \frac{-1 - 3}{-3 - 3}[/tex]
[tex]m = \frac{-4}{-6}[/tex]
Simplify to lowest term
[tex]m = \frac{2}{3}[/tex]
Next is to determine the equation of the line using the slope formula
[tex]m = \frac{y - y_1}{x - x_1}[/tex], [tex](x_1, y_1) = (3,3)[/tex] and [tex]m = \frac{2}{3}[/tex]
[tex]\frac{2}{3} = \frac{y - 3}{x - 3}[/tex]
Cross multiply
[tex]2 * (x - 3) = 3 * (y - 3)[/tex]
Open both brackets
[tex]2 x - 6 = 3y -9[/tex]
Collect like terms
[tex]2 x - 6 +9= 3y[/tex]
[tex]2 x+3= 3y[/tex]
Divide through by 3
[tex]\frac{2x}{3} + \frac{3}{3} = \frac{3y}{3}[/tex]
[tex]\frac{2x}{3} + 1 = y[/tex]
Reorder
[tex]y = \frac{2x}{3} + 1[/tex]
Next is to determine the inequality sign
The dotted lines on the graph shows that the inequality sign is either > or <Since the shaded region is the upper part of the graph, then the > inequality sign will be considered,The inequality becomes
[tex]y > \frac{2x}{3} + 1[/tex]
Please answer this question now in two minutes
Answer:
q = 4 mi
Step-by-step explanation:
Using the sine or cosine ratio in the right triangle and the exact value
sin45° = [tex]\frac{1}{\sqrt{2} }[/tex] , then
sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{q}{4\sqrt{2} }[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] ( cross- multiply )
[tex]\sqrt{2}[/tex] × q = 4[tex]\sqrt{2}[/tex] ( divide both sides by [tex]\sqrt{2}[/tex] )
q = 4
The following data points represent the number of children in each household on Maple Street. \qquad 0, 1, 2, 1, 20,1,2,1,20, comma, 1, comma, 2, comma, 1, comma, 2 Find the mean number of children.
Answer:
The mean number of the children is 1.2
Step-by-step explanation:
Given
Children: 0, 1, 2, 1, 2
Required
Determine the Mean number
The mean of a set is calculated as follows;
[tex]Mean = \frac{\sum x}{n}[/tex]
Where x is the given set and n is the number of sets
In this case, n = 5 children
Hence;
[tex]Mean = \frac{0 + 1 + 2 + 1 + 2}{5}[/tex]
[tex]Mean = \frac{6}{5}[/tex]
[tex]Mean = 1.2[/tex]
Hence, the mean number of the children is 1.2
find tan(a) in the triangle
Answer:
tan (a) = 24/7Step-by-step explanation:
tan∅ = opposite / adjacent
From the question
AC is the adjacent
BC is the opposite
So we have
tan (a) = BC / AC
tan (a) = 24/7
Hope this helps you
find the reciprocal of.
Answer:
a) 3/1 that is 3
b) 8/7
c) the mixed fraction is converted into simple fraction: 3*2+2/3 = 8/3
therefore the reciprocal is 3/8
d) 1/5
e) the mixed fraction is converted into simple fraction: 6*6+1/6 = 37/6
therefore the reciprocal is 6/37.
plz mark my ans as branlliest and like it upvote it
plz follow me and in return i wil also follow you.
Answer:
a. [tex]3[/tex]
b. [tex] \frac{8}{7} [/tex]
c. [tex] \frac{3}{8} [/tex]
d. [tex] \frac{1}{5} [/tex]
e. [tex] \frac{6}{37} [/tex]
Step-by-step explanation:
a. [tex] \frac{1}{3} [/tex]
Just flip the fraction , you will get:
[tex] = \frac{3}{1} [/tex]
[tex] = 3[/tex]
b. [tex] \frac{7}{8} [/tex]
flip the fraction
[tex] = \frac{8}{7} [/tex]
c. [tex]2 \frac{2}{3} [/tex]
The first thing you have to do is that convert mixed fraction into improper fraction
[tex] \frac{8}{3} [/tex]
Flip the fraction
[tex] = \frac{3}{8} [/tex]
d. [tex]5[/tex]
flip the fraction
[tex] = \frac{1}{5} [/tex]
e. [tex]6 \frac{1}{6} [/tex]
Convert mixed fraction into improper fraction
[tex] = \frac{37}{6} [/tex]
Flip the fraction in order to get reciprocal
[tex] = \frac{6}{37} [/tex]
Hope this helps...
Best regards!!
Help :(
Yun was trying to factor 7x^2- 14x. He found that the greatest common factor of these terms was 7x and made an area model:
What is the width of Yun's area model?
Answer:
If the question is saying that length is 7x, then the answer (width) is x-2
Write as an algebraic expression and simplify if possible:
100% of x
What is the answer?
Answer: simplified algebraic expression : x
Step-by-step explanation:
The given phrase : 100 % of x
We can write 100 as 1 because 100% means complete or entire part.
Also, replace 'of' by '×' (Multiply sign).
So, the given phrase will become
1 × x [Algebraic expression]
= x [Simplified]
hence, the simplified algebraic expression is 'x'.
Third-degree, with zeros of −5, −4, and 1, and a y-intercept of −15
Answer:
y = 3/4( x+5)( x+4) ( x-1)
Step-by-step explanation:
The formula for the polynomial is
y = c( x- a1)( x- a2) ( x-a3) where c is a constant and a1,a2,a3 are the zeros
We have zeros -5,-4 and 1
y = c( x- -5)( x- -4) ( x-1)
y = c( x+5)( x+4) ( x-1)
We have a y intercept of -15
That means x=0 and y = -15
-15 = c ( 0+5)( 0+4) ( 0-1)
-15 = c( 5) ( 4) (-1)
-15 = c( -20)
Divide each side by -20
-15/-20 = c
3/4 =c
The equation is
y = 3/4( x+5)( x+4) ( x-1)
Find each product.
(X3+2x2)x4
PLEASE HELP!!! ASAP!!!
Answer:
4x^3+8x^2
Step-by-step explanation:
Multiply each term:
4x^3+8x^2
PLZ MARK ME BRAINLIEST
In 1995, Derek Jeter's batting average was 0.250; in 1996, his batting average was 0.314. David Justice's batting average in 1995 was 0.253 and was
0.321 in 1996. The team statistician claims Jeter's overall average was better than Justice's average. What may make this claim possible?
Sampling error
Cause-and-effect relationship
Convenience error
Simpson's Paradox
Confounding
Answer:
The correct option is;
Simpson Paradox
Step-by-step explanation:
The phenomenon whereby particular trends are prevalent in small data portions but are not evident or an inverse trend is observe when the portions are joined together is known as Simpson's paradox.
Whereby the data for calculating the bating averages as found online are given as follows;
Season, Derek Jeter David Justice
1995, 12/48 = 0.250 104/411 ≈ 0.253
1996, 183/582 ≈ 0.314 45/140 ≈ 0.321
The overall hits to the overall bats ratio are;
, (183 + 12)/(582 + 48) ≈0.310 (104+45)/(411+140) = 0.27
Which shows that Derek Jeter's overall average was better than Justice's average
Ellen thinks if it has no slope it never touches the y axis , what can prove that her Statement is correct
Answer:
y+0
As y=0 represent x-axis whose slope is 0 and intersects y-axis at the origin.
a subway train with 47 people stops at a station and picks up 20 more people at the same station p people get off. there are 52 people left on the train. which equation shows how to find the value of p
Answer:
67 - p = 52
Step-by-step explanation:
the train starts with 47 people: 47
it picks up 20 more: 47 + 20 = 67
p people get off: 67 - p
52 people are left on train: 67 - p = 52
Now, you will use the inverse trig function to solve. Round to the nearest whole number. x= ∘ What trig function would we use to set up our trig function to solve for y?
Answer:
1. Cosine
2. x = 49°
3. Sine
4. y = 41°
Step-by-step explanation:
1. The trig function that will be used to solve for x is cosine.
2. Determination of angle x
x° =..?
Adjacent = 13
Hypothenus = 20
Cos x = Adjacent /Hypothenus
Cos x = 13/20
Take the inverse of Cos
x = Cos¯¹ (13/20)
x = 49°
3. The trig function that will be used to solve for y is sine.
4. Determination of angle y.
y° =..?
Opposite = 13
Hypothenus = 20
Sine y = Opposite /Hypothenus
Sine y = 13/20
Take the inverse of Sine
y = Sine¯¹ (13/20)
y = 41°
did this several times but still didn't get the answer .pls do try this :)
Answer:
x=-15/2 and x=1
x=6 and x=3/4
Step-by-step explanation:
You have the following equations:
[tex]\frac{4x-3}{x+2}=\frac{2x}{x+5}[/tex]
[tex]\frac{2}{x-2}+\frac{3}{x}-\frac{9}{x+3}[/tex]
To solve both equations you can first multiply by the m.c.m of the denominators, and then solve for x, just as follow:
first equation:
[tex][\frac{4x-3}{x+2}=\frac{2x}{x+5}](x+2)(x+5)\\\\(4x-3)(x+5)=2x(x+2)\\\\4x(x)+4x(5)-3(x)-3(5)=2x(x)+2x(2)\\\\4x^2+20x-3x-15=2x^2+4x\\\\4x^2-2x^2+20x-3x-4x-15=0\\\\2x^2+13x-15=0[/tex]
In this case you use the quadratic formula:
[tex]x_{1,2}=\frac{-13\pm \sqrt{(13)^2-4(2)(-15)}}{2(2)}\\\\x_{1,2}=\frac{-13 \pm 17}{4}\\\\x_1=-\frac{15}{2}\\\\x_2=1[/tex]
Then, for the first equation the solutions are x=-15/2 and x=1
second equation:
[tex][\frac{2}{x-2}+\frac{3}{x}=\frac{9}{x+3}]x(x-2)(x+3)\\\\2x(x+3)+3(x-2)(x+3)=9x(x-2)\\\\2x^2+6x+3(x^2+3x-2x-6)=9x^2-18x\\\\2x^2+6x+3(x^2+x-6)=9x^2-18x\\\\2x^2+6x+3x^2+3x-18-9x^2+18x=0\\\\-4x^2+27x-18=0[/tex]
Again, you use the quadratic formula:
[tex]x_{1,2}=\frac{-27\pm \sqrt{(27)^2-4(-4)(-18)}}{2(-4)}\\\\x_{1,2}=\frac{-27\pm 21}{-8}\\\\x_1=6\\\\x_2=\frac{3}{4}[/tex]
Then, the solutions for the second equation are x=6 and x=3/4
Just for the bottom 2 please
Answer:
c is 35
d is 13
Step-by-step explanation:
I multiplied both sides, and then simplified the equation.
( plz give me brainliest, that would be most appreciated! )
WILL MARK BRAINLIEST!!!!PLZ HELP!!!! An expression is shown below: 3pf2 − 21p2f + 6pf − 42p2 Part A: Rewrite the expression by factoring out the greatest common factor. Part B: Factor the entire expression completely. Show the steps of your work.
Answer:
See Below.
Step-by-step explanation:
We have the expression:
[tex]3pf^2-21p^2f+6pf-42p^2[/tex]
Part A:
Find the GCF. Notice that we have a three in every term and a p in every term. Thus, the GCF will be 3p. Factor:
[tex]3p(f^2-7pf+2f-14p)[/tex]
This is the most we can do.
Part B:
Continuing from where we left off, we can factor the entire expression by grouping:
[tex]\displaystyle \begin{aligned} &= 3p(f^2-7pf+2f-14p) \\ \\ &= 3p(f(f-7p)+2(f-7p)) \\ \\ &=3p((f+2)(f-7p))\end{aligned}[/tex]
PLEASE help me solve this question! I really need to solve this question ASAP! No nonsense answers, and please attach the solution.
Answer:
{-0.5, 0.1}
Step-by-step explanation:
multiply the 8 on the left with x/x so you can write left hand as [tex]\frac{1-8x}{x}[/tex]cross multiply to get rid of the fractions: [tex]5x = (1-8x)(5x+2)[/tex]simplify into a regular quadratic equation: [tex]-20x^2 - 8x +1 =0[/tex]use the quadratic formula to get the answers:[tex]x = \frac{8 \pm \sqrt{(-8)^2 - 4 \cdot -20 \cdot 1}}{-40} = \frac{8 \pm 12}{-40}[/tex]
so x is 20/-40 = -0.5 or x = -4/-40 = 0.1
HELP!
Andrea has a $25 gift card
to a art store. She buys four canvases that are each the same price. If she now has $2.20 on her gift card, what was the price of each canvas?
Answer:
$5.70
Step-by-step explanation:
1. 25.00 - 2.20 = $22.80
2. 22.80 divided by 4 = $5.70
Answer:
$5.70
Step-by-step explanation:
let the price for each canvas be $x
hence the price of 4 canvases will be $4x
It is given that after she paid for 4 canvases, she had a balance of $2.20 on her orginally $25 gift card.
Hence we can assemble an equation:
$4x + $2.20 = $25
4x + 2.2 = 25 (subtract 2.2 from both sides)
4x = 25 - 2.2
4x =22.8 (divide both sides by 4)
x = 22.8 / 4
x = 5.7
Hence each canvas cost $5.70
3( 2x + 1 ) = 15 you have to find x
Answer:
x = 2
Step-by-step explanation:
3(2x+1) = 15
6x +3 = 15
6x = 12
x - 2
Simplify $\dfrac{1}{\sqrt2+1}+\dfrac{1}{\sqrt2-1}.$
Answer:
2√2
Step-by-step explanation:
By simplifying we get the value is [tex]2\sqrt{2}[/tex]
What is expression ?The combination in which numbers, variables, functions are present, is called expression.
Example : 6y-3x+2, 2y-3 etc.
What is the simplified form of the expression ?
The given expression is [tex]\frac{1}{\sqrt{2}+1 } +\frac{1}{\sqrt{2}-1 }[/tex]
Simplifying,
First we take the LCM of [tex]\sqrt{2}+1[/tex] & [tex]\sqrt{2}-1[/tex]
Then expression becomes, [tex]\frac{(\sqrt{2}-1)-(\sqrt{2}+1) }{(\sqrt{2}+1)(\sqrt{2}-1)}[/tex]
Now, using [tex](a+b)(a-b)=a^{2}- b^{2}[/tex] we get, [tex]\frac{\sqrt{2}-1+\sqrt{2}+1 }{(\sqrt{2}) ^{2} - 1^{2} }[/tex]
Now, simplifying, we get, [tex]\frac{2\sqrt{2} }{2-1}[/tex] = [tex]2\sqrt{2}[/tex]
Learn more about expression here :
https://brainly.com/question/4344214
#SPJ2
Josephine is going on a run around the lake. She knows the distance around the lake, but she would like to complete her run
in a certain amount of time. Josephine knows she can used the formula d = rt.
Which equation correctly rearranges the formula to find the time it will take her to run around the lake?
A. T= d/r
B. T= r/d
C. T=d + r
D. T=d-r
Hey there! I'm happy to help!
We want to see which of the formulas is a correct rearrangement of d=rt. To figure this out, we will solve each of our answer options for d. If d is equal to rt, then that option is the correct rearrangement.
OPTION A
t=d/r
We flip the equation around so d is on the left side.
d/r=t
We multiply both sides by r.
d=tr
Using the associative property, we see that d=tr is the same thing as d=rt.
We immediately see that this is the correct option. Therefore, the answer is A. T=d/r.
From the original d=rt, equation, we see that they solved for t by dividing both sides by r, giving you t=d/r.
Have a wonderful day! :D
Can someone help fast please
Answer:
B
Step-by-step explanation:
Just reduce your x's and y's. The x^-1 cancels with the x^5, and the y^-9 and y^-3 get simplified. After some basic simplifying, you get answer B.
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.
Answer:
The logarithmic parent function is the only one with negative numbers in the range
Step-by-step explanation:
Hello,
These functions have been very well known, I remind you their graphs below
The logarithmic parent function is the only one with negative numbers in the range
range for square root is [tex]\mathbb{R^{+}}[/tex]
range for logarithmic is [tex]\mathbb{R}[/tex]
range for exponential is [tex]\mathbb{R^{+}}[/tex]
THAT S TRUE
The square root and logarithmic parent functions have the same domain
domain for square root is [tex]\mathbb{R^{+}}[/tex]
domain for logarithmic is [tex]\mathbb{R}[/tex]
THAT S WRONG
The square root parent function domain is the most restricted
domain for square root is [tex]\mathbb{R^{+}}[/tex]
domain for exponential is [tex]\mathbb{R^{+}}[/tex]
THAT S WRONG
All three parent functions have the same domain
domain for square root is [tex]\mathbb{R^{+}}[/tex]
domain for exponential is [tex]\mathbb{R^{+}}[/tex]
domain for logarithmic is [tex]\mathbb{R}[/tex]
THAT S WRONG
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
HIIIIII 2 QUESTIONS IN THE 2 PICS HELP PLS
Answer:
(1)C- Trapezoid
(2)D-20 square feet
Step-by-step explanation:
Question 1
A cross-section of a rectangular pyramid cut perpendicular to the base but not passing through the top will have two parallel sides where one of the sides will be longer. Therefore, the shape which describes the cross-section will be a trapezoid.
Question 2
The base of the Triangle = 5 feet
Height of the Triangle = 8 feet
[tex]\text{Area of a triangle}=\dfrac12 \times $Base \times Height\\=\dfrac12 \times 5 \times 8\\=20 ft^2[/tex]
Multiply the polynomial
10. (3-2v)(2-5v)
11. (5x-4)(3x2+x-5)
Answer:
10) [tex]10v^2-19v+6[/tex]
11) [tex]15x^3-7x^2-29x+20[/tex]
Step-by-step explanation:
Well first let's make the box.
10)
Look at the image below ↓
[tex]10v^2-19v+6[/tex]
11)
Look at the image below ↓
[tex]15x^3-7x^2-29x+20[/tex]
Thus,
number 10 is [tex]10v^2-19v+6[/tex] and number 11 is [tex]15x^3-7x^2-29x+20[/tex].
Hope this helps :)
what is the product number of 88 and 26?
Answer:
2288
Step-by-step explanation:
how to do this question plz answer me step by step plzz
Answer:
30, 85, 95, 150
Step-by-step explanation:
The angles of a quadrilateral add to 360
Let x be the smallest angle
x+55
x+65
x+120 are the other three angles
Add the 4 angles together and they sum to 360
x+x+55 x+65+ x+120 = 360
Combine like terms
4x+240 = 360
Subtract 240 from each side
4x+240-240 = 360 -240
4x = 120
Divide by 4
4x/4 = 120/4
x = 30
x+55= 30+55 = 85
x+65 = 30+65 = 95
x+120 = 30+120 = 150
Enter a range of values for x.
85°
25
5x - 10
[ ? ]
Enter
==================================================
Explanation:
We'll use the hinge theorem here. This says (more or less) that the larger an angle is, the side opposite of that will be longer.
Imagine that the segments with the single tickmarks represent a door swinging open/shut. The more open a door is, the further the distance it is from the handle to the frame. In terms of these triangles, the segment 25 is larger than 5x-10 because the angle 90 (opposite the 25) is larger than the angle 85 degrees (opposite the 5x-10)
In symbols we say
5x - 10 < 25
We also say 5x - 10 > 0 or 0 < 5x - 10 to ensure that the segment of length 5x-10 is not 0 or negative.
Put the two inequalities together and we get 0 < 5x - 10 < 25
------------
Solve for x
0 < 5x - 10 < 25
0+10 < 5x - 10 < 25 + 10 .... adding 10 to all sides
10 < 5x < 35
10/5 < 5x/5 < 35/5 ... dividing all sides by 5
2 < x < 7
We have x between 2 and 7, and not equal to either endpoint.
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the pad. He used 2 more sheets in his second class than in his first. How many sheets are left for his third class? ill give brainliest to the first answer
Answer:
Colin has 8 sheets left for his third class.
Step-by-step explanation:
Given that:
Total Number of pieces of papers = [tex]x[/tex]
Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad
Writing the equation:
[tex]\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)[/tex]
Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.
[tex]\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)[/tex]
Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class
[tex]\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8[/tex]
So, the answer is:
Colin has 8 sheets left for his third class.
3 over 3 fourths divided by 5 over 7
Answer:
5.6
Step-by-step explanation:
(3÷3/4)÷5/7
[tex] \frac{3 \times 4}{3} \div \frac{5}{7} [/tex]
[tex]4 \div \frac{5}{7} [/tex]
[tex]4 \times \frac{7}{5} [/tex]
[tex] \frac{28}{5} [/tex]
=5.6
use "keep, change, flip " when dividing a number by a fraction.
keep the whole number
flip the divide sign to multiply
change the placement of number e.g. 5/7 becomes 7/8
then solve