When two trains, going in opposite directions, are passing on tracks that are laid out close together, the train cars can often be seen to be leaning in toward one another where they are in proximity. How might the air passing through the narrow gap separating the two trains contribute to the observed attraction between their cars?

Answer:

[tex]0.629\ \text{rad/s}^2[/tex] counterclockwise

[tex]9.98\ \text{s}[/tex]

Explanation:

[tex]r_1[/tex] = Small drive wheel radius = 2.2 cm

[tex]\alpha_1[/tex] = Angular acceleration of the small drive wheel = [tex]8\ \text{rad/s}^2[/tex]

[tex]r_2[/tex] = Radius of pottery wheel = 28 cm

[tex]\alpha_2[/tex] = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

[tex]r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2[/tex]

The angular acceleration of the pottery wheel is [tex]0.629\ \text{rad/s}^2[/tex].

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

[tex]\omega_i[/tex] = Initial angular velocity = 0

[tex]\omega_f[/tex] = Final angular velocity = [tex]60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}[/tex]

t = Time taken

From the kinematic equations of linear motion we have

[tex]\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}[/tex]

The time it takes the pottery wheel to reach the required speed is [tex]9.98\ \text{s}[/tex]

The distance Oscar covered was 6km while the displacement was 2km.

Displacement is defined as the vector whose length is the shortest

distance from the initial to the final position of a point M.

Distance = Total length of space between points

              = 2km+ 2km+ 2km = 6km.

Displacement = 2km.

This is because it is the shortest  distance from the positions in this

scenario.

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Answer:

i think is c

Explanation:

Answer:

C

Explanation:

C makes more sense than D, Because it says the minimum value is when it stays at rest.

Answer:

The sum of an object's potential and kinetic energies is called the object's mechanical energy. As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy.

Explanation:

Answer:

the potential decrease and kinetic increase

Explanation:

because it goes from a state of rest to a state of movement

Answer:

Option D: 1

Explanation:

The chemical equation given is;

2NaCl = 2Na + XCl2

We want to find the value of X.

On the left hand side, we can see we have 2 moles of both Na and Cl.

On the right hand side, we can see that we have 2 moles of Na and also 2 moles of Cl. Thus, the equation is balanced and as such X = 1

Answer:

A.

Explanation:

Some of these photons are absorbed by the atoms in the ground state and the photons are lost to the laser process. However, some photons cause stimulated emission in excited-state atoms, releasing another coherent photon. In effect, this results in optical amplification

Answer:

Drink water

Make your find fresh by doing the stuff you love too ❤️

Answer:

Instantaneous velocity  [tex]= 20[/tex] meter per second

Instantaneous acceleration  [tex]= 6[/tex] meter per second square

Explanation:

Given equation of distance X = [tex]2t+3t^2[/tex]

Instantaneous velocity [tex]= \frac{dX}{dt}[/tex]  [tex]= 2 + 6 t[/tex]

Substituting the value of t = 3 seconds, we get -

[tex]\frac{dX}{dt} = 2 + 6*3 = 20[/tex] meter per second

Instantaneous acceleration  [tex]= \frac{d^2X}{dt^2}[/tex]  [tex]= 6[/tex] meter per second square

Answer:

C

Explanation:

if you measure your body's flexibility then you can keep track of how flexible you have gotten over time

In Linear motion the swimmer swims

Answer: A

Explanation: Linear motion.

Answer:

A. Trial and error

Explanation:

Trial and error method is a method adopted when trying to solve a quadratic equation. This equation is mostly the balancing of the right hand side and the left hand side in-order to form a unique point or to equate to zero when one is subtracted from the other. In trail and error method, the coefficients is used to determine when the actual equation is balanced and the likely answer it should be if the equation is expanded through multiplication method.

Answer:

[tex]5.896\times 10^{-7}\ \text{m}[/tex]

Explanation:

D = Distance of the screen from the light source = 2.2 m

d = Distance between slits = 0.46 mm

m = Order

Distance between adjacent bright fringes is 2.82 m

[tex]y_{m+1}-y_m=2.82\ \text{mm}\\\Rightarrow \dfrac{D(m+1)\lambda}{d}-\dfrac{Dm\lambda}{d}=2.82\times 10^{-3}\\\Rightarrow \dfrac{D\lambda}{d}(m+1-m)=2.82\times 10^{-3}\\\Rightarrow \lambda=\dfrac{d}{D}2.82\times 10^{-3}\\\Rightarrow \lambda=\dfrac{0.46\times 10^{-3}\times 2.82\times 10^{-3}}{2.2}\\\Rightarrow \lambda=5.896\times 10^{-7}\ \text{m}[/tex]

The wavelength of the light that falls on the slits is [tex]5.896\times 10^{-7}\ \text{m}[/tex].

Answer:

because they conduct heat and electricity and vibrate the neighboring molecules

plz mark me branliest

Answer:

The first answer is correct.  All of the other options include sound, which travels by material force, and can not be transmitted in a vacuum.  Infra-red, radio, and microwaves are all different frequencies of light, and can thus travel through a vacuum.

Answer:

-40 degrees

Explanation:

I just took the Temperature Quiz and got it right. :)

a centrifugal clutch works, as the name suggests, through centrifugal force. ... The rotation of the hub forces the shoes or flyweights outwards until they come into contact with the clutch drum, the friction material transmits the torque from the flyweights to the drum. The drive is then connected

Answer: 10 Ω or 2.5 Ω

Explanation:

In series resistance R = 5 Ω + 5 Ω =10 Ω. If resistors are parallel, resistance is

1/R = 1/5Ω+ 1/5Ω and R = 2,5 Ω

[tex] \Large {\underline { \sf {Required \; Solution :}}}[/tex]

We have ―

We've been asked to calculate acceleration.

[tex]\qquad \implies\boxed{\red{\sf{ a = \dfrac{v-u}{t} }}}\\[/tex]

[tex] \twoheadrightarrow \quad \sf {a = \dfrac{30-18}{3} \; ms^{-2} } \\ [/tex]

[tex] \twoheadrightarrow \quad \sf {a =\cancel{ \dfrac{12}{3} \; ms^{-2} }} \\ [/tex]

[tex]\twoheadrightarrow \quad \boxed{\red{\sf{ a = 4 \; ms^{-2} }}}\\[/tex]

Therefore, acceleration of the car is 4 m/s².

Answer:

100 milliliters

Explanation:

Answer:

19.9 N/m

Explanation:

From the question,

Applying Hook's law

F = Ke.................. Equation 1

Where F = Force on the spring, k = spring constant, e = extension

But the force on the spring is the weight of the mass

Therefore,

mg = ke.................. Equation 2

Where m = mass. g = acceleration due to gravity

make e the subject of the equation

e = mg/e................ Equation 3

Given: m = 455 g = 0.455 kg, e = 22.4 cm = 0.224 m,

Constant: g = 9.8 m/s²

Substitute these values into equation 3

e = (0.455×9.8)/0.224

e = 19.9 N/m

The spring constant of the given spring is 20 N/m.

The given parameters:

The spring constant is calculated by applying Hooke's law as follows;

[tex]F = kx\\\\mg = kx\\\\k = \frac{mg}{x} \\\\k = \frac{0.455 \times 9.8}{0.224} \\\\k = 20 \ N/m[/tex]

Thus, the spring constant of the spring is 20 N/m.

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Answer:

1. Rₑq = 4 Ω

2. R₂ = 6 Ω

3. Vₜ = 12 V, V₁ = 12 V, V₂ = 12 V

4. Iₜ = 3 A, I₁ = 1 A, I₂ = 2 A

Explanation:

1. Determination of the equivalent resistance

Voltage (V) = 12 V

Current (I) = 3 A

Resistance (Rₑq) =?

V= IRₑq

12 = 3 × Rₑq

Divide both side by 3

Rₑq = 12 / 3

Rₑq = 4 Ω

Thus, the equivalent resistance (Rₑq) = 4 Ω

2. Determination of R₂.

Equivalent resistance (Rₑq) = 4 Ω

Resistance 1 (R₁) = 12 Ω

Resistance 2 (R₂)

Since the resistor are in parallel arrangement, the value of R₂ can be obtained as follow:

Rₑq = R₁ × R₂ / R₁ + R₂

4 = 12 × R₂ / 12 + R₂

Cross multiply

4(12 + R₂) = 12R₂

48 + 4R₂ = 12R₂

Collect like terms

48 = 12R₂ – 4R₂

48 = 8R₂

Divide both side by 8

R₂ = 48 / 8

R₂ = 6 Ω

3. Determination of the total voltage (Vₜ), V₁ and V₂.

From the question given above, the total voltage is 12 V

Since the resistors are arranged in parallel connection, the same voltage will go through them.

Thus,

Vₜ = V₁ = V₂ = 12 V

4. Determination of the total current (Iₜ), I₁ and I₂

From the question given above, the total current (Iₜ) is 3 A

Next, we shall determine I₁. Since the resistors are arranged in parallel connection, different current will pass through each resistor respective.

Vₜ = V₁ = 12 V

R₁ = 12 Ω

I₁ =?

V₁ = I₁R₁

12 = I₁ ×12

Divide both side by 12

I₁ = 12 / 12

I₁ = 1 A

Next, we shall determine I₂. This can be obtained as follow:

Iₜ = 3 A

I₁ = 1 A

I₂ =?

Iₜ = I₁ + I₂

3 = 1 + I₂

Collect like terms

I₂ = 3 – 1

I₂ = 2 A

cold, dry, and stable air masses .

Answer:

2000 N.

Explanation:

From the question given above, the following data were obtained:

Load (L) = 8000 N

Mechanical advantage (MA) = 4

Effort (E) =?

The mechanical advantage of a machine is simply defined as:

Mechanical advantage = Load / Effort

MA = L / E

With the above formula, we can obtain the effort used to raise the load of 8000 N as follow:

Load (L) = 8000 N

Mechanical advantage (MA) = 4

Effort (E) =?

MA = L / E

4 = 8000 / E

Cross multiply

4 × E = 8000

Divide both side by 4

E = 8000 / 4

E = 2000 N

Thus, the effort used to raised the load is 2000 N.

From the diagram, the fossil of fish is considered the oldest fossil. Because the oldest fossils are formed at the bottom whereas the others are at the top of the soil.

When living organisms like plants, animals, and human beings are died, their  bodies get buried in the form of sediments in the sand, rock water bodies, etc..,

It also includes the preserved remains of life for more than 10,000 years. It is the preserved remains, sediments, and impressions to trace the life of the organisms and their behavior.

When living organisms died and are buried in sand or mud, the tissues of living organisms get decomposed leaving the bones which is harder. After the organisms are buried in the sand or mud, several sediments, and sand was built over the top of the buried organisms.

These sand and sediments over the buried organisms eventually form the layer of rocks. This is how fossils are made and these fossils were identified when the rocks were broken or by cause of soil erosion.

The age of the fossils was identified by the stacks of layered rocks with the help of the superposition principle. The oldest fossils are present at the bottom of the rocks whereas the youngest fossils are present at the top of the rocks. This process is called Relative dating.

Hence, from the given diagram the fossil of fish is present at the bottom of the rock unlike the others fossils like monkeys and lizard. Thus, the oldest fossil is fish and the youngest one is a monkey.

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Answer:

θ = 22.2

Explanation:

This is a diffraction exercise

        a sin θ = m λ

The extension of the third zero is requested (m = 3)

They indicate the wavelength  λ = 630 nm = 630 10⁻⁹ m and the width of the slit  a = 5 10⁻⁶ m

         sin  θ = m λ / a

         sin  θ = 3 630 10⁻⁹ / 5 10⁻⁶

         sin  θ = 3.78 10⁻¹ = 0.378

          θ = sin⁻¹  0.378

to better see the result let's find the angle in radians

          θ = 0.3876 rad

let's reduce to degrees

         θ = 0.3876 rad (180º /π rad)

         θ = 22.2º

Answer:

correct answer is C

Explanation:

In this exercise, you are asked to complete the sentences so that the sentence makes sense.

1) in projectile launching, the only force that acts is gravity in the vertical direction, so the time of going up is EQUAL to the time of going down

correct answer C

2) when a body falls freely, the acceleration is the ratio of gravity, therefore if it starts from rest, its height is

            y = v₀ t - ½ gt²

v₀ = 0

             y = -1/2 g t²

so the position is not proportional to the square of the time

correct answer is C

Answer:

 v = 4.8 10⁻⁴ m / s

Explanation:

To solve this exercise we can use the concepts of energy. In this case the potential energy is transformed into kinetic energy

          U = K

          q V = ½ m v²

          v = [tex]\sqrt { \frac{2qV}{m} }[/tex]

in the exercise they indicate the value of the charge q₁ = 1 pC = 1 10⁻¹² C

let's calculate

          v = [tex]\sqrt{ \frac{2 \ 1 \ 10^{-12} 120 \ 10^3}{500 ^{2} }[/tex]

          v = 4.8 10⁻⁴ m / s

Explanation:

When there is a high frequency sound the speed of the vibrations is faster and makes a high pitch sound. When there is a low frequency sound the speed of the vibrations is slower and makes a lower pitch sound.