Write a program that prompts the user to enter a Social Security number in the format ddd-dd-dddd, where d is a digit. The program displays Valid SSN for a correct Social Security number or Invalid SSN otherwise.

ssn = input("Enter a valid Social Security number: ")

dashes = 0

nums = 0

message = "Invalid SSN"

if len(ssn) == 11:

   for x in ssn:

       if x.isdigit():

           nums += 1

       elif x == "-":

           dashes += 1

if nums == 9 and dashes == 2:

   message = "Valid SSN"

print(message)

I wrote my code in python 3.8. I hope this helps!

The program that prompts the user to enter a Social Security number in the format ddd-dd-dddd, where d is a digit can be implemented in Python using regular expressions. The regular expression pattern for the SSN format can be used to validate the input.

Pythons code:

```python

import re

ssn_pattern = re.compile(r'^\d{3}-\d{2}-\d{4}$')

ssn = input("Enter your Social Security Number (format: ddd-dd-dddd): ")

if ssn_pattern.match(ssn):

print("Valid SSN")

else:

print("Invalid SSN")

```

In the above code, we first import the `re` module to work with regular expressions.

We then define the regular expression pattern for the SSN format as `^\d{3}-\d{2}-\d{4}$`. This pattern matches any string that starts with three digits, followed by a hyphen, then two digits, another hyphen, and finally, four digits.

We then prompt the user to enter their SSN using the `input()` function. We then check if the entered SSN matches the pattern using the `match()` function of the regular expression object `ssn_pattern`.

If the SSN matches the pattern, we print "Valid SSN". Otherwise, we print "Invalid SSN".

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